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bingo
自己做的两个小病毒和一个控制开关机的程序。。。小病毒求大神指点aaa(Own two small virus and a control switch procedure. . . The god of small viruses seek advice aaa)
- 2013-12-26 18:46:40下载
- 积分:1
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TCP
使用C++ MFC编写的简易TCP通信程序,包括客户端和服务端两个程序(A TCP communication program written by C++ MFC, including client and server)
- 2020-08-31 19:48:11下载
- 积分:1
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MediaPlayerVc
桌面系统下的一个小播放器,可以播放多种格式的媒体文件,测试可用.(Desktop systems to a smaller player, can play multiple formats of media files, testing can be used.)
- 2009-10-15 14:19:40下载
- 积分:1
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Love
c++显示爱心,3D显示,表白可用,怒求推荐(c++ show love, 3D display, confession Tools)
- 2015-09-11 16:04:51下载
- 积分:1
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11.21九宫格抽奖系统
11.21九宫格抽奖系统VSC#编程代码(11.21 9 Gongge Draw System VSC# Programming Code)
- 2019-03-12 14:34:05下载
- 积分:1
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VC
说明: 伽马函数求解C语言,用来求解伽马函数的C语言 求解干嘛函数用的(The gama gan and de is gama you are )
- 2010-06-13 23:51:27下载
- 积分:1
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medo
设X[ 0 : n - 1]和Y[ 0 : n – 1 ]为两个数组,每个数组中含有n个已排好序的数。找出X和Y的2n个数的中位数。 编程任务 利用分治策略试设计一个O (log n)时间的算法求出这2n个数的中位数。 数据输入 由文件input.txt提供输入数据。文件的第1行中有1个正整数n(n<=200),表示每个数组有n个数。接下来的两行分别是X,Y数组的元素。结果输出 程序运行结束时,将计算出的中位数输出到文件output.txt中(Let X [0: n- 1] and Y [0: n- 1] for the two arrays, each array containing the n number has been sorted. 2n X and Y to identify the number of digits. programming tasks using the divide and conquer strategy try to design an O (log n) time algorithm to calculate this median number 2n. Data input by the input data provided input.txt file. The first line in the file has a positive integer n (n < = 200), that there are n numbers of each array. The next two lines are the X, Y array elements. The end result is output program runs, the calculated median output to file output.txt)
- 2021-03-22 16:29:16下载
- 积分:1
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YasVPS_Src
之前计划写的沙盘系统,刚写好文件部分,也不算太完善,碰巧有人问起,遂贴上代码大家看去,你可以在此基础上完善之。 代码没什么WS技术,但做文件沙盘还是有不少问题的,需要的朋友可以下(Written before the planned sand table system, just part of the written document, but also not too perfect, someone happened to ask, accordingly paste the code we looked, you can improve on this basis, the. Code no WS technology, but do still have many issues paper sand table, and we need friends can, under)
- 2009-12-12 11:39:12下载
- 积分:1
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读写优先
事件对象解决读写者问题实现P、V操作用Win32提供的同步对象实现P、V操作,并使用它们解决读者-写者问题
利用事件机制模拟多值信号量。(Event object solves the problem of reader writer)
- 2020-10-26 14:29:59下载
- 积分:1
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programmingguide
C++程序设计教程第二版 钱能
part I Basic Programming
part II Procedural Programming
part III Object-Oriented Programming
(C++ Programming Guide (second edition ))
- 2009-03-05 23:53:51下载
- 积分:1