Cheby

利用MATLAB编写的高斯消去法，很好用，也很实用(using MATLAB write Gass)

code for matlab simulation o fsensor nettworks

牛顿拉夫逊法潮流计算程序，已测试40个节点，内附参考结果和典型系统的描述，很全的资料(Newton Raphson power flow program, 40 nodes have been tested, the results and typical system containing a reference to the description, it is all the information)

说明：  matlab的各种自适应仿真分析。。自适应信息处理的算法、方案繁多，究其实质可归纳为遵循最小均方误差(Least Mean Square，LMS)准则及最小二乘(Least Square，LS)准则两大类，其他算法大多是这两种算法的演进。(matlab simulation analysis of various adaptive. . Adaptive information processing algorithms, a variety of plans, their essence can be summarized as follows the minimum mean square error (Least Mean Square, LMS) criterion and least squares (Least Square, LS) criteria for two categories, most of the two other algorithms kind of algorithm evolution.)

一份智能控制的课程报告，包括PID参数整定的简便有效方法及模糊控制器的设计,包含二者的详细matlab仿真,及其结果对比，可以依葫芦画瓢。(Course report intelligent control, including PID parameter tuning and design a simple and effective method of fuzzy controller, containing both detailed matlab simulation, and the results were compared, can Yihuhuhuapiao.)

说明：  图像处理（验证码识别）程序 内含事例(Image processing (validation code identification) program contains examples of)

adaboost代码，比较简单。但方便了解Adaboost算法的基本原理(The aim of the project is to provide a source of the meta-learning algorithm known as AdaBoost to improve the performance of the user-defined classifiers. )

In machine learning, artificial neural networks (ANNs)

在做复合形法优化时，用到《精通MATLAB最优化设计》一书中的复合形法程序，发现做其他例题时运行不了。去掉bug后，改进如下，如果你遇到同样问题，不妨下来试试。如果你没有Funval.m，可以将程序中的Funval函数换成subs(In doing complex method optimization, use the " Mastering MATLAB Optimization Design," a book of complex method program, found other examples can not do when running. After removing the bug, improvements are as follows, if you encounter the same problem, we might try it. If you do not Funval.m, the program can be replaced by a function of Funval subs)

Evaluate the value of an arithmetic expression in Reverse Polish Notation. Valid operators are +, -, *, /. Each operand may be an integer or another expression. Some examples: [ 2 , 1 , + , 3 , * ] -> ((2 + 1) * 3) -> 9 [ 4 , 13 , 5 , / , + ] -> (4 + (13 / 5)) -> 6 分析：这一题就是写程序计算逆波兰式的结果，遍历表达式，碰到操作数入栈，碰到操作符就从栈顶取出两个操作数，再将计算后的结果入栈，最后栈中剩余的唯一操作数就是计算结果。(. Evaluate the value of an arithmetic expression in Reverse Polish Notation Valid operators are+,-,*,/Each operand may be an integer or another expression Some examples:.. [" 2" , " 1" , " +" , " 3 " ," * " ]-> ((2+ 1)* 3)-> 9 [" 4 " ," 13 " ," 5 " ," /" ," + " ]-> (4+ (13/After this problem is to write a program to calculate the inverse Polish results, iterate expression operand stack encounter, encounter operator to fetch two operands the stack, and then calculated as follows:> 6 Analysis- 5)) The results of the stack, the only remaining operand stack is the final calculations.)