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fz
说明: 关于MATLAB能量检测频谱感知算法的研究代码(MATLAB energy detection on spectrum sensing algorithm code)
- 2011-03-23 17:17:52下载
- 积分:1
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ofdm
说明: 真对无线通信中的正交频分复用的matlab仿真源代码。(True for wireless communications in orthogonal frequency division multiplexing matlab simulation source code.)
- 2009-09-02 09:07:22下载
- 积分:1
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MATLABC-C
MATLABC数学函数库在C语言中的应用(MATLABC math library in C language)
- 2012-10-08 10:08:01下载
- 积分:1
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Matlab-senior-notes(3)
Matlab高级讲义-控制系统的数学描述与建模(Matlab senior notes- the mathematical description of the control system and modeling)
- 2011-12-24 21:12:57下载
- 积分:1
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2010-04-15_Balanced_PSO
Balanced PSO,可作为benchmark比较(You campare your algorithm with it.)
- 2013-09-21 10:22:38下载
- 积分:1
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FPE
说明: 按FPE定阶的
源程序:fpe.cpp
M序列:M序列.txt
白噪声:Gauss.txt
程序中先用依模型阶次递推算法估计模型的参数,再用fpe方法判断模型的阶次。
程序运行结果如下:
n: 1
判断阶次FPE的值: 0.0096406
-0.481665 1.07868
n: 2
判断阶次FPE的值: 0.00875755
-0.446739 0.00498181 1.07791 0.0527289
n: 3
判断阶次FPE的值: 0.0087098
-0.459433 0.120972 -0.0569228 1.07814 0.0390757 0.116982
n: 4
判断阶次FPE的值: 0.000396884
-0.509677 0.4501 -0.200906 0.0656188 1.07991 -0.0156362 0.442989 0.0497236
n: 5
判断阶次FPE的值: 3.2095e-007
-1.18415 0.813123 -0.517862 0.34881 -0.116864 1.07999 -0.744141 0.474462 -0.253112 0.122771
n: 6
判断阶次FPE的值: 3.23349e-007
-1.14659 0.76933 -0.487651 0.329676 -0.10377 -0.00440907 1.07999 -0.703574 0.447253 -0.235282 0.113587 0.00479688
从以上结果可以看出,当n=5时,fpe值最小,所以这时的模型阶次和参数估计值为最优结果:
3.2095e-007
-1.18415 0.813123 -0.517862 0.34881 -0.116864 1.07999 -0.744141 0.474462 -0.253112 0.122771(err)
- 2008-09-12 01:14:14下载
- 积分:1
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charu
请输入非递减的有序序列,输入-1结束,再输入一个数字,插入其中,按照从小到大的顺序进行排列,完成这个程序(Please enter a non-decreasing ordered sequence, enter-1 end, and then enter a number, into which, in ascending order of arrangement, complete this program)
- 2014-11-15 18:50:27下载
- 积分:1
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example4_3
例3:分析占空比为ta的矩形脉冲频谱
T=1 时间窗大小
ta=0.5 占空比
N=256
t=linspace(-T,T,N)
ts=2*T/N
fs=1/ts
(x=zeros(1,N)
x(N/2-round(N/2*ta):N/2+round(N/2*ta))=ones(1,2*round(N/2*ta)+1)
y=fft(x,N)
figure
plot(t,x)
title([ 时域信号图 占空比为 ,num2str(ta)])
axis([-T T-0.2 1.2])
xlabel( t /s )
figure
subplot(211)
f=linspace(-fs/2,fs/2,N)
plot(f,abs(fftshift(y))/N)
title([ 矩形脉冲双边谱 脉冲时间t=[- ,num2str(ta*T), , ,num2str(ta*T), ] ])
xlabel( f /Hz )
)
- 2010-05-25 20:59:59下载
- 积分:1
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bypass-UAC-souce-code
本代码可以实现绕过win7UAC(用户账户控制),可以很好的实现(This code can realize to bypass win7UAC, (User Account Control), can achieve a good)
- 2013-04-19 11:37:28下载
- 积分:1
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ask
Amplitude Shift Keying Simulation
- 2011-09-10 15:44:06下载
- 积分:1