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primary
大规模MIMO系统导频分配问题的一种分配方案基础性的代码(A fundation method of pilot arrangement on massive MIMO)
- 2021-04-18 13:28:57下载
- 积分:1
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2 DVR
说明: Simulation for comparison of DVR and Other compensating devices
- 2021-02-13 13:34:32下载
- 积分:1
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Introduction-to-MATLAB---Sikander-M.-Mirza
Introduction to Mathlab ebook
- 2012-03-25 21:32:46下载
- 积分:1
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spectral_efficiency
Computing the spectral efficiency of the STBC
- 2012-09-09 18:40:30下载
- 积分:1
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matlab_tutorial
为南京邮电大学的MATLAB教程,精通MATLAB辅导与提高,内附例程。(Nanjing University of Posts and Telecommunications of the MATLAB tutorials, counseling and improving proficiency in MATLAB, enclosing routine.)
- 2008-01-13 20:32:53下载
- 积分:1
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nurbsR2006b
说明: 非均匀有理B样条的matlab程序,其中用到了C的混合编程。对于学习数据融合技术的人很有帮助!(Non-uniform rational B-spline matlab program, which uses a mixture of C programming. Data fusion technology for the study of people very helpful!)
- 2008-10-30 00:14:51下载
- 积分:1
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Sonar_Exp_v2_CW
声纳技术 常用水声信号及其处理方法 内容 CW信号(Commonly used in underwater acoustic signal processing method)
- 2012-04-15 08:54:09下载
- 积分:1
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vector-control
Vector control programming
- 2012-04-23 21:16:14下载
- 积分:1
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lawmask
statistical methods in order to extract image texture descriptors. In particular, we will focus on the Co-occurrence matrices and the Energy
filters (Laws filters). They are well-known texture descriptors, fast and easy to implement and provide good results that could be used in a
posterior step to perform image segmentation and object recognition.(statistical methods in order to extract image texture descriptors. In particular, we will focus on the Co-occurrence matrices and the Energyfilters (Laws filters). They are well-known texture descriptors, fast and easy to implement and provide good results that could be used in aposterior step to perform image segmentation and object recognition.)
- 2008-01-26 23:28:29下载
- 积分:1
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c9_estimatepi
%File: c9_estimatepi.m
%有5个pi的估计,每一个都是基于500次重复随机试验,所得的pi的五个估计值用以下向量表示
%pi的估计值=[3.0960 3.0720 2.9920 3.1600 3.0480]
%如果对5个结果进平均,则pi的估计值=3.0736,这样的结果等价于2500次的试验结果。( File: c9_estimatepi.m have 5 pi estimates are based on a randomized trial to repeat 500 times the income of the five estimated value of pi with the following vector, said the estimated value of pi = [3.0960 3.0720 2.9920 3.1600 3.0480] if the results into an average of 5, then the estimated value of pi = 3.0736, so the result is equivalent to 2500 times the test results.)
- 2006-11-05 10:30:13下载
- 积分:1