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pcmcode
律u律pcm编码
若输入A律PCM编码器的正弦信号为x(t)=sin(1600πt),采样序列为x(n)=sin(0.2πn),n=0,1,2,…,10,将其进行PCM编码,求出编码器的输出码组序列y(n)。
要求:1) 直接采用A律扩展器函数求解上述问题。
2)使用13折线法近似A律PCM 求解上述问题。
3)计算量化误差。(Law a law pcm coding
If the input A-law PCM encoder is sinusoidal signal x (t) = sin (1600πt), for the sample sequence x (n) = sin (0.2πn), n = 0,1,2, ..., 10, it will be PCM coding to obtain the coded output code group sequence y (n).
Requirements: 1) directly A-law expander function to solve the above problems.
2) using a 13 fold line approximation A-law PCM to solve the above problems.
3) calculating the quantization error.)
- 2016-04-06 19:30:12下载
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- 2013-10-21 21:36:35下载
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