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Matlab_Colour_Transfer_using_IDT_Pitie07
进行图像颜色的传输,使源图像变为目标图像颜色(Color image transmission, so that the source image to target image color)
- 2009-02-23 18:56:33下载
- 积分:1
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textscantool
MATLAB中textscantool,非常好,大家支持啊(MATLAB, textscantool, very good, we support ah)
- 2010-10-20 18:28:05下载
- 积分:1
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work
用matlab实现牛顿向前插值,代码简单易懂,适合初级matlab学习者。(Newton forward interpolation using matlab implementation, code easy to understand, matlab for elementary learners.)
- 2010-05-20 08:09:41下载
- 积分:1
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demo1
This is the demo file for L1 adaptive controller with a simple unknown parameter:
dot x(t) = Ax(t) + b(u(t) - heta^ op x(t))
DoSims.m: This script initializes the model parameters, run the simulation
L1Model_sec1.mdl:the implementation of L1 adaptive controller.
Refer to the following paper for background:
C. Cao, N. Hovakimyan, Design and Analysis of a Novel Adaptive Control Architecture with Guaranteed Transient Performance, IEEE Transactions on Automatic Control, vol.53, No.2, pp. 586-591, 2008.
- 2012-08-27 05:09:01下载
- 积分:1
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water_filling_algorithm
关于注水算法的简单演示。在总功率受限的情况下通过功率分配逼近香农信道容量(performs the water filling algorithm with the given total power constrain to approach Shannon capacity of the channel.)
- 2013-12-13 11:20:19下载
- 积分:1
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genetic-algorithm
单变量遗传算法,内附测试函数,算法简单可行,效率较高(genetic algorithm for single variable function)
- 2015-03-22 11:19:55下载
- 积分:1
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GUI
一个实例搞定MATLAB界面编程 pjimage.m(matlab m_file)
- 2014-11-29 10:47:46下载
- 积分:1
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PV_module_model
photovoltaic model pdf fotovoltaik solar energy pdf
- 2013-04-02 03:19:35下载
- 积分:1
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3-chapter
《MATLAB 7.0编程基础基础》源程序 第3章(Chapter 3 of the " MATLAB 7.0 programming foundation foundation source)
- 2012-11-15 14:15:31下载
- 积分:1
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hypot
抛物线法求解
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.(parabolic equation method Construction Methods : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2014-04-25 08:18:59下载
- 积分:1