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audio_demo
语音信号处理:This package encloses a small application dedicated to speech signal processing
at 8 kHz or 16 kHz. This application reads standard *.wav or *.pcm files through UI dialog box, plots and plays the signal with vertical dynamic crosshairs.(This package encloses a small application dedicated to speech signal processing at 8 kHz or 16 kHz. This application reads standard*.wav or*.pcm files through UI dialog box, plots and plays the signal with vertical dynamic crosshairs.)
- 2010-06-05 18:19:00下载
- 积分:1
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standfor
some thing more for MIMO
- 2009-03-09 23:23:06下载
- 积分:1
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BPSKRAYLEIGHFADING
bpsk in Rayleigh fading
- 2009-04-19 14:59:11下载
- 积分:1
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bifmapadeikeda
Bifurcation Digram of Ikeda map
- 2013-01-09 14:27:16下载
- 积分:1
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ds
说明: 本文件是用matlab来实现的D-S证据理论代码。可以进行DS证据理论的推到验证(This document is achieved by matlab code DS evidence theory. DS evidence theory can be pushed to the validation)
- 2011-06-06 11:17:12下载
- 积分:1
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Zfund_tutorial5b
Matlab tutorial part 5 for beginners
- 2011-01-08 01:23:46下载
- 积分:1
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houghlines
实现在matlab环境下的直线检测,效果很好(Straight line detection, with good results achieved in the matlab environment)
- 2012-11-18 17:02:31下载
- 积分:1
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GARDNER
16 进制QAM信号的GARDNER算法定时同步(timing Synchronize for16 QAM)
- 2017-08-08 17:29:35下载
- 积分:1
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josephsonmatlab
本程序基于约瑟夫森结的RSJ模型,对无微波辐照和微波辐照下约瑟夫森结的特性进行了数值计算求解,其中有微波辐照的RSJ模型求解采用了四阶龙格库塔方程函数,两种情况都给出了I-V特性曲线图(程序包中也附带),展现了量子化电压台阶。(This procedure based on the RSJ Josephson junction model, no microwave radiation and microwave radiation characteristics of Josephson junction has been calculated solving, in which microwave radiation has the RSJ model for solving a fourth-order Runge-Kutta equation function In either case, they are given IV characteristic curve chart (also included with the package), demonstrating the quantum level of voltage.)
- 2007-08-24 13:16:39下载
- 积分:1
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c
说明: 编写一个函数,输入n为偶数时,调用函数求1/2+1/4+...+1/n,当输入n为奇数时,调用函数
1/1+1/3+...+1/n(利用指针函数)
(Write a function, the input n is even, the function call seeking 1/2+1/4+...+ 1/n, when the input n is odd, call the function 1/1+1/3+...+ 1/n (using the pointer function))
- 2011-07-18 09:28:07下载
- 积分:1