chap5_6plant

说明：  学习电力电子时搭建的正激变换器，PI环是移植的TI的代码，欢迎交流。(Learning power electronics to build the forward converter, PI ring is transplanted TI code, welcome to exchange.)

利用一个中断和定时器解码不占用CPU过多资源，解码NEC格式的红外遥控器(Using an interrupt and timer decoding does not occupy CPU too many resources, decoding NEC format infrared remote control.)

说明：  Zigbee的开发资料，包括原理图和PCB图(Development materials of Zigbee, including schematic and PCB diagrams)

电子万年历c语言程序 有闹钟 整点报时 年月日与时分秒转换 有闹钟查看功能(Electronic calendar c language program with alarm the whole point of time when minutes and seconds years on and the conversion function with alarm view)

CMAC小脑神经网络模型，基于matlab，供学习交流(CMAC cerebellar neural network model, based on MATLAB, for learning and communication)

SIM868_mini板 用户手册 Spec说明(SIM868_mini Spec document)

第十二届全国大学生智能车电磁组源代码，整车程序 本人(The Twelfth National College Students intelligent vehicle electromagnetic group source code)

C#做的一个简易的IE浏览器，只是一个浏览器的主窗口，可打开指定的url，不过功能不多，界面挺干净，基于Windows的IE核心，C#2010可编译源码，运行界面效果参见截图。

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

有关于VC操作Word的程序，自动调整图标序号的部分-on VC Word operating procedures, automatic adjustment of serial icon