FDRPSO

基于多总线的飞机电气故障模拟实验系统设计Multi-bus-based simulation of aircraft electrical system failure(Multi-bus-based simulation of aircraft electrical system failure)

用LMS算法实现自适应均衡器的MATLAB程序(LMS algorithm using adaptive equalizer in the MATLAB program)

Matlab project which is in parts. so please collect all 10 parts. then extract it and enjoy.

无线传感器网络方向，最快的选择传输的路径(Wireless sensor networks direction, choose the fastest transmission path)

非常好的应用软件，欢迎大家抢购使用,非常非常好非常好非常好非常好非常好非常好(very beautiful ,please come and buy)

将含有高斯白噪声的输入信号通过线性系统后（带阻滤波器）的输入、输出前信号的频谱、功率谱对比。同时给出了线性系统特性(Gaussian white noise, containing the input signal by a linear system (bandstop filter) of the input, before the output signal spectrum, the power spectrum of contrast. Also gives a linear system characteristics)

adaptive algorithms using matlab software: Error_Minimization_Equation_Error Error_Minimization_Output_Error MIT_Rule_Equationt_Error MIT_Rule_Output_Error Projection_Algorithm

Identify queue length By edge detection without blocking

直流电动机 降压软启动 simulink模型 参考(Step-down DC Motor soft-start simulink model reference)

在一个移动通信系统中，发射信号是一个未调制的音频x(t)=cos(2πft)，其中f=f0+fi。设标称载波为f0=1GHz，并设fi =512Hz。假定移动用户在一个繁忙的高速公路上距离基站l公里处的地方，从开始从每小时60公里的速度开始，其速度（在0.01秒的时间间隔内测量）以1/2的概率随机的增加或减少1/10公里每小时。试仿真移动用户在这2s的时间间隔内所接收到的信号(及其频谱)。接收信号可以表示为： y(t)=a(t)Cos[2π(fo+f1)(t-△t)] 式中 △(t)=d(t)/c 且 a(t)=k/d2(t) 在上面的表达式中d(t)是在t时刻基站与移动用户的距离，c是光速，△(t)是传播延迟，而a(t)是信号在t时刻的衰减，并假设在这2s内a(t)是一个常数。利用复低通等效模型来进行仿真。(In a mobile communication system, the transmitted signal is an unmodulated audio x (t) = cos (2πft), where f = f0+ fi. Let nominal carrier of f0 = 1GHz, and set fi = 512Hz. Assume that mobile users on a busy motorway station l kilometers place, starting the beginning of 60 kilometers per hour, the speed (measured in 0.01 second interval) to increase the probability of a random 1/2 or reducing 1/10 km/h. Simulation test signal which the mobile subscriber in the 2s time intervals of the received (and its spectrum). The received signal can be expressed as: y (t) = a (t) Cos [2π (fo+ f1) (t- △ t)] Where △ (t) = d (t)/c And a (t) = k/d2 (t) In the above expression, d (t) at time t is a base station and a mobile user s distance, c is the speed of light, △ (t) is the propagation delay, and a (t) is the attenuation of the signal at time t, and assuming that 2s within a (t) is a constant. Using complex low-pass equivalent model for emulation.)