MINRES

PB反编译工具，支持源码查看和导出undw可以导出数据窗口。(PB decompiler tool, support source code view and export undw can export data window.)

进程防杀.rar 一般的杀毒软件都关不掉-The process of anti-killing. Rar general anti-virus software off can not afford to

视频插件，暴风影音必备，包含Real Player 10和Quick Time 6.5的核心组件，请不要和其各自对应的原始（官方）版本一同安装，否则会发生冲突-Video Plug-in, CD-essential Storm, Real Player 10 includes Quick Time 6.5 and the core components, Please do not and their respective counterparts of the original (official) version installed together, otherwise it would conflict

数独解法，能够解不要求回溯的数独问题，目前只支持用户自己出题。-Sudoku Solution, to the solution does not require backtracking Sudoku problem, currently only supports the user

数值计算方法相关的十个程序 包括对分法,迭代法,牛顿法,割线法,高斯消元法,雅克比迭代法程序,幂法,线性拟合态,()

说明：  该文档是数字通信第五版的课后答案，英文版的答案(This document is the answer to the fifth edition of digital communication after class and the answer to the English edition.)

1. There are at least 10 nodes in the simulation and each node has at least two neighbors within its transmission area. 2. Every node periodically broadcasts a ”request” packet to its neighbors. Meantime, this node sets a timer with t time interval to wait for its neighbors ”re- sponse” packets. When receiving all responses from its neighbors during t, it prints ”success”; oth- erwise, it prints ”failure”. Assume that the broadcast periodical interval is bigger than t. 3. A neighbor that receives a ”request” packet, sends a ”response” packet after a random time τ , τ = random(0, 2t).(There are at least 10 nodes in the simulation and each node has at least two neighbors within its transmission area. Every node periodically broadcasts a request packet to its neighbors. Meantime, this node sets a timer with t time interval to wait for its neighbors response packets. When receiving all responses from its neighbors during t, it prints success oth- erwise, it prints failure. Assume that the broadcast periodical interval is bigger than t.)

一个简单的JSP OA办公系统，包括考勤管理、人事管理、费用管理、人力资源管理、资料管理、资产管理、个人工具、工作计划管理、车辆管理等，还具备下拉菜单功能，在JSP中实现OA管理系统的时候，这些代码可作为一个参考吧。

运用伸展树的特性，每次插入新的结点后，调用展开函数，使得新结点成 为所建树的根结点。(Use of the characteristics of the splay tree, each time you insert a new node, call to function, making the new node into For the achievements of the root.)

使用说明. 一、为什么要进行大气纠正? （1） 太阳辐射通过大气以某种方式入射到物体表面 ... 用户可以选择MODTRAN 模型的光谱分辩率. 三、如何使用FLAASH. 打开FLAASH ... -modtan