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dsc-single-sideband-modulation
说明: dsc单边带调制。功能是用10Hz的载波信号去调制频率为500Hz的基带信号,然后得到单边带调制信号(single-sideband modulation)
- 2011-04-01 10:15:56下载
- 积分:1
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tet-mesh
A program which computes various quality measures for a tet mesh of a set of nodes in 3D
- 2013-01-15 18:33:59下载
- 积分:1
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abcab
abc quantity to alpha beta conversion
- 2012-08-25 08:11:44下载
- 积分:1
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ImageRegistrationApp
it is used to dtect upper body
- 2015-01-10 13:39:26下载
- 积分:1
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chaos-time
混沌吸引子的MATLAB程序的实现,在这个基础上可以去掉前面的暂态点,调整视角,全方位地观察混沌吸引子的几何结构。(Chaotic attractor MATLAB program implementation, on this basis can be removed in front of the transient point, adjust the viewing angle in all directions to observe the geometry of chaotic attractors.)
- 2009-09-23 19:00:13下载
- 积分:1
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Poisson_FEM
poisson问题有限元求解通用程序(线性元).
压缩包内exp.m包含了一个实际问题,matlab下直接运行即可,如效率不高,可适当修改网格参数h.(poisson problem of the finite element procedure for solving general (linear million). exp.m compressed package contains a real problem, matlab can be directly run, such as the efficiency is not high, may be appropriate to amend the grid parameter h.)
- 2007-12-01 09:41:07下载
- 积分:1
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estimation1
正太分布的贝叶斯参数估计,写的很详细,很有用(This code is based on the Bayesian threshold segmentation, very useful)
- 2012-05-07 23:34:31下载
- 积分:1
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rcos_dsp
升余弦滚降系统的源程序(用于调制解调系统中波形成型)(Raised Cosine system of the source (for modulation and demodulation waveform prototyping system))
- 2007-05-11 16:32:19下载
- 积分:1
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meanshift
matlab实现的meanshift算法,本人使用效果不错(meanshift on matlab )
- 2010-12-25 11:24:41下载
- 积分:1
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advancenewton
说明:
改进的牛顿法求解:
方程的构造方法:给出[0,1]区间上的随机数(服从均匀分布)作为方程的根p*.
设你的班级数为a3,学号的后两位数分别为a2与a1,从而得到你的三次方程
例如:你的31班的12号,则你的方程是21x3+60x2+2x+a0=0的形式.
方程中的系数a0由你得到的根p*来确定.
(improve Newton's method : Construction of the equation : given interval [0,1] on the random number (subject to uniform distribution) as the root equation p*. set up your classes at a3, after learning of the double-digit for a1 and a2, so you get the three equations for example : Your 31 classes on the 12th, then your equation is 21x3 60x2 2x a0 = 0 forms. the equation coefficients a0 you get from the root of p* to determine.)
- 2005-12-03 18:16:08下载
- 积分:1