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v6-code
sound localization code using the matlab. this is a simulation file
- 2012-03-27 02:01:35下载
- 积分:1
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JISUANQI
使用gui编写的计算器功能,与windows上计算器类似(A calculator written in GUI)
- 2020-06-15 22:55:01下载
- 积分:1
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00466915
Tracking and Recognizing Rigid and Non-Rigid Facial Motions
using Local Parametric Models of Image Motion
- 2013-07-17 13:58:02下载
- 积分:1
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tracker-code-2011.11.18
This software was developed under Linux with Matlab R2009a.
There is no guarantee it will run on other operating systems or Matlab versions.
- 2012-02-13 20:26:38下载
- 积分:1
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alamouti
alamouti結合ofdm系統下
做的仿真系統。 提供大家討論使用
不懂的再與我聯絡吧(alamouti combination of OFDM systems to do the simulation system. U.S. to discuss the provision of re-use and I do not know how to contact you)
- 2008-04-15 22:19:22下载
- 积分:1
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Matlab-learning-book-codes
selected matlab codes for numerical analysis numerical differentiation and root finding. Euler anf Ronge Kotta
- 2014-12-26 09:10:21下载
- 积分:1
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ypea122-spea2
说明: 遗传算法 多目标优化算法,SPEA2
主要流程:1:首先初始化一个archive的集合P1,以及一个常用的population的集合P。设置P1的大小是N1,P的大小是N。初始的时候P1是空的,而P是已经初始化好的种群个体。
2:对P1进行评价,选出来里面的pareto front为1(下面用PF1来代替了)的个体,copy到P1中,如果PF1的数量大于N1的话,这个接下来再说,目前假定PF1的数量小于N1。(Genetic algorithm, multi-objective optimization algorithm, SPEA2
Main process: 1: first, initialize a set P1 of archive and a set P of popular. Set P1 to N1 and P to n. At the beginning, P1 is empty, and P is the initialized population.
2: Evaluate P1, select the individual whose Pareto front is 1 (Pf1 is used to replace it below), copy to P1, if the number of Pf1 is greater than N1, then let's talk about it. At present, it is assumed that the number of Pf1 is less than N1.)
- 2021-03-01 14:59:00下载
- 积分:1
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C-C-method
运用C-C算法重构相空间重构嵌入维数和计算时间延迟(Using C-C reconstruction of phase space reconstruction algorithm embedded dimension and computing time delay)
- 2012-04-11 16:07:18下载
- 积分:1
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FastICA_NE
FastICA算法的盲源分离程序,为函数,输入混合信号矩阵即可。(FastICA algorithm of blind source separation program for the function, the input signal matrix can be mixed.)
- 2011-10-25 16:41:21下载
- 积分:1
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step reponse
说明: step response of control system
- 2019-06-22 18:24:10下载
- 积分:1