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MathematicalStatistics
数理统计与MATLAB的原程序,供大家学习交流(Mathematical Statistics with MATLAB original procedures for the exchange of U.S. study)
- 2009-03-14 09:39:52下载
- 积分:1
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2
说明: matlab程序设计基础ppt 函数文件程序设计的基本结构(matlab program design based on function ppt document the basic structure of program design)
- 2008-10-07 21:12:09下载
- 积分:1
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1
说明: QPSK通过Rayleigh信道多径衰落的Matlab仿真 (无)
- 2010-04-18 16:47:14下载
- 积分:1
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GAmean_distance
This function is used to determine the mean distance
for uniform sampling over a hypercube. Used for comparing the
quality of initial conditions with other algorithms that use
only one iterative solution (i.e., can use mean distance here
to set i.c. with same mean distance in single solution algorithm).
thetatmax
- 2010-01-07 20:43:29下载
- 积分:1
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PCoCS
线性调频信号(LFM)是雷达信号处理中的常见信号形式。
雷达成像中通过距离和方位2个方向的脉冲压缩实现高分辨成像。
附件中对这一技术的实现和误差分析进行了MATLAB仿真。(LFM (LFM) radar signal processing is a common signal format. Radar imaging distance and direction through the direction of two pulse compression to achieve high-resolution imaging. Annex to the realization of this technology and error analysis of MATLAB simulation carried out.)
- 2010-06-28 21:17:41下载
- 积分:1
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chap11
syms x
g=exp(x*sin(x))
t=taylor(g,12,2)
xd = 1:0.05:3 yd = subs(g,x,xd)
ezplot(t, [1,3]) hold on
plot(xd, yd, r-. )
title( Taylor approximation vs. actual function )
legend( Taylor , Function )(syms x g = exp (x* sin (x)) t = taylor (g, 12,2) xd = 1:0.05:3 yd = subs (g, x, xd) ezplot (t, [1 , 3]) hold on plot (xd, yd, ' r-.' ) title (' Taylor approximation vs. actual function' ) legend (' Taylor' , ' Function' ))
- 2011-07-27 18:12:56下载
- 积分:1
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attachments_2013_04_28-kahina
this code is about vissel blood extraction by matlab
- 2013-05-07 01:21:50下载
- 积分:1
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fractual
多重分形算法 用于图像的处理和边缘图像用多重分形技术检测。(Multifractal algorithm)
- 2013-01-22 21:53:46下载
- 积分:1
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模式识别
电子科大matlab作业实例,可以进行参考(Matlab example of UESTC)
- 2020-07-10 20:38:54下载
- 积分:1
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anquanguohe
先定义允许状态S={(x,y)|x=0或3,y=0,1,2,3 x=y=1,2},
允许决策D={(u,v)|u+v=1,2},求dk<-D(k=0,1,2,…,n),使
状态Sk<-S按照状态转移律S(k+1)=S(k)+(-1)^k*dk,由初始状态
S1=[3,3]经有限步到达状态S(n+1)=[0,0].此为求解多步决策问题( First define to allow the state S = ((x, y) | x = 0 or 3, y = 0,1,2,3 x = y = 1,2), to allow the decision-making D = ((u, v) | u+ v = 1,2), seek dk < -D (k = 0,1,2, ..., n), so that state Sk < -S state transition in accordance with law S (k+1) = S (k )+ (-1) ^ k* dk, from the initial state S1 = [3,3] by the finite-step to reach the status S (n+1) = [0,0]. This is a multi-step decision-making problem solving)
- 2010-02-17 12:02:50下载
- 积分:1