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1
说明: 倒立摆数学模型及分析及建模叙述,主要是过程(Pendulum mathematical model and analysis)
- 2014-11-26 22:29:14下载
- 积分:1
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Cangjiepian
find nearby No. in Cangjiepian.
- 2014-06-30 15:57:06下载
- 积分:1
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prog-final
PROGRAM hich is used to implement a back steeping and robust control with trajectory generation for planaire robot of two degree of freedem
- 2013-09-30 18:03:17下载
- 积分:1
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newton
it is useful for my research
- 2013-12-21 13:57:04下载
- 积分:1
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system_identification_qpsk
随机产生一QPSK调制信号,通过一随机产生的低通滤波器,然后使用LMS算法实现了系统哦你的辨识。(Randomly generate a QPSK modulation signal generated by a random low-pass filter, and then use the LMS algorithm of the system Oh, your identification.)
- 2010-12-13 23:32:53下载
- 积分:1
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TE
说明: 用matlab求解TE模的导模参数,传播常数,入射角度等(Guided mode parameters using matlab to solve the TE mode ,such as propagation constant,the angle of incidence)
- 2012-12-21 10:15:39下载
- 积分:1
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nan_simulation
水电机组仿真,发电机组采用菲利普斯描述。输出信号为有功功率和频率,适用于控制类电气仿真。(Hydro-generator simulation, the generator set described by Phillips. The output signal for the active power and frequency, suitable for control of electrical simulation.)
- 2021-04-19 16:28:51下载
- 积分:1
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5
一道程序编译顺序的考题,涉及到函数调用的先后顺序及运算符号的优先级等问题。下面我展开给你讲。
C的程序编译总是从main函数开始的,这道题的重点在“fun((int)fun(a+c,b),a-c)) ”语句。
系统首先要确定最外层 fun()函数的实参,第一个参数的确定需要递归调用fun()函数(不妨称其为内层函数)。内层函数的两个参数分别为x=a+b=2+8=10、y=b=5,执行函数体x+y=10+5=15,于是得外层函数的参数x=15。其另一个参数y=a-c=2-b=-6,再次执行函数体,得最终返回值x+y=15+(-6)=9。 (Compiling together the sequence of test procedures, involving the sequence of function calls and operator symbols, such as the priority problem. Now I give you to start speaking. Procedures for C compiler always start from the main function and at这道题the focus of " fun ((int) fun (a+ c, b), ac)) " statement. System must first determine the most outer layer of fun () function of real parameters, the first parameters of recursive calls required fun () function (may be called the inner function). Inner function separately for the two parameters x = a+ b = 2+8 = 10, y = b = 5, to execute the function body x+ y = 10+5 = 15, then the outer function parameters were x = 15 . Its another parameter y = ac = 2-b =- 6, once again to execute the function body may eventually return the value of x+ y = 15+ (-6) = 9.)
- 2009-03-15 15:36:23下载
- 积分:1
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qq
说明: system initialisation in matlab
- 2010-04-21 02:03:33下载
- 积分:1
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Introduction_to_Fuzzy_Logic_using_MATLAB
Useful for fuzzy logic.
- 2012-01-02 20:13:56下载
- 积分:1