小小的计算器程序

C语言输入输出不同数据类型格式转换问题，字符串和数值-C language input and output data types different format conversion, and numerical string

测试工具jmeter可用来进行性能测试，功能测试以及数据库访问性能测试-Jmeter testing tool can be used to conduct performance testing, functional testing and performance testing database access

这是一个有关考试登陆系统的程序-This is a landing system for the examination procedures

各种门电路模型的VerilogHDL描述-various gates model of Verilog HDL description

JAVA2游戏程序设计源码，图书光盘源码！-JAVA2 game programming source code, books CD-ROM Source!

学生成绩管理系统 C语言 1、掌握结构化设计方法。 2、了解大型软件的设计技术 3、在实际应用背景下灵活运用线性表的顺序存储结构和链式存储结构。 4、灵活运用线性表上的各种基本运算，完成题目需求。 5、在实例中运用排序与查找算法。-student performance management system a C language, master structural design methods. Two, understand the design of large software technology 3, in the context of practical applications flexibility in the use of the linear sequence table storage structure and chain storage structure. 4, the flexible use of linear form of basic computing, completed topic demand. 5, in the example with the use of ranking search algorithm.

有关CAD/CAM的资料,希望对大家有帮助-Related to CAD/CAM data, and they hope to have everyone help

个人财务管理系统，不过还有一个模块没有完成，都是在控制台中完成的。 这是我第一个自己做的，希望大家多多指点！-Personal financial management system, but there is a module not yet been completed, are completed in the console. This is my first one to do their own, and I hope a lot of pointing everyone!

文件移动MOVE的C语言源程序代码 开发环境为C-documents Mobile MOVE C language source code development environment for C

学生成绩核算系统的设计与实现（25） 要求：（1）按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 （2）三个成绩对总评成绩的百分比被定义为常数，各占总成绩的30 、30 和40 。 （3）计算每位学生的总评成绩。 （4）计算该班级本课程的总平均成绩。 （5）计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优，89-80为良，79-70为中，69-60为及格，60分以下为不及格。 （6）按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop