这是一个JAVA帮助文档,我在这里上传是为了帮JAVA初学者一个平台,让我们的JAVA事业能有一个新的台阶,我们这里为我们JAVA爱好者能够一起努力.为JAVA...

通过DX的D3D实现一组图片的简单的动画功能,对于大家理解动画的动作方式很有帮助.-through DX D3D achieve a group photo of a simple animation functions, we can understand the animation moves very helpful way.

定时提醒（可设：提醒；提醒并关机；直接关机；定时执行一程序等。是家长们控制孩子玩电脑的好帮手。-regularly reminded (can be installed : Warning; Advised and shutdown; Directly elected; Timing implementation of a procedure. parents controlled their children playing with the computer"s helping hands.

是关于模糊聚类的c语言程序，效果不错的模，糊聚类分析 模糊聚类 聚类分析 FUZZY 模糊C-MATLAB

基于umat编译用户子程序来计算二维复合材料层合板的分层失效，以及疲劳应力计算，可以用于复合材料的分析。其中应用fortran语言定义了各个变量及失效判据。

this is a railway reservation system

提供了一个很好的工具给广大航海人帮助，了解国际航海规则-Provides a good navigational tools to the broad masses of people to help, understanding of international navigation rules

开发工具,很好用的!希望大家多多支持 -Development tools, a good use! Hope everyone can support

这里提供的是电力系统潮流计算机解法的五个子程序,采用的方法是Newton_Raphson法-provided here is the power flow solution to the five computer subroutine the method used was Newton_Raphson France

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

LED点阵显示牌的设计与动态显示控制3.PDF-q