software encryption, do not need to buy Security Dog, Johnson ah. Doing an encry...

程序目的：两个多项式相加　-procedures Objective : add two polynomials

当有入侵者远程登 录时会及时给我们发出报警。要想能够及时发 出报警信息．就要用到短信报警，方便快捷-When a remote intruder to log in a timely manner, we will issue a report to the police. To be able to give timely warning information. Alarm SMS will be used, convenient and quick

Matrix 11: Matrix template library 相当好用-Matrix 11: Matrix template library very easy to use

汤姆斯旺C＋＋编程秘诀，下载后解压缩即可-Thomas Wong C programming tips, download can decompress

一个用TXT写的程序，看了说明后就知道怎么用了，据说是世界程序设计大赛第一名，真的很难相信是人写出来的-a program writen in text. Read the introduction to use it. It said that it got the first place in world programming competition. Hard to believe it was writen by a person.

VC与matlab的结合，VC中调用Matlab测试代码-VC and Matlab, the combination of VC Calling Matlab test code

这是一个数据加密的程序。有些初学者可能已经习惯了。

将数据从串口数据从gsm接受收器中读出，显示出来-Data from the serial port to accept data from the collection device in gsm read out, displayed

VCLZip控件的经典使用全集。可以通过VCLZip控件提供的方法、属性实现Zip压缩文件的制作，实现类似WinZip软件的功能。-All classical classes of control VCLZip. It use to develop Zip compress file software with it s functions and properties provided, likes WinZip functions.

图像压缩问题要求确定象素序列{p1,p2,…,pn}的最优分段，使得依此分段所需的存储空间最少。每个分段的长度不超过256位。数字化图像是m×m的像素阵列。假定每个像素有一个0 ~ 2 5 5的灰度值。因此存储一个像素至多需8位。若每个像素存储都用最大位8位，则总的存储空间为8m^2 位。为了减少存储空间，我们将采用变长模式（ variable bit scheme），即不同像素用不同位数来存储。像素值为0和1时只需1位存储空间； 值2、3各需2位；值4，5，6和7各需3位；以此类推。-image compression defined pixel sequence (p1, p2, ..., pn) sub-optimal, sub accordingly makes the storage space required at least. The length of each section is not more than 256. The digital image is m m pixel arrays. Assume that each pixel is a 0-2 5 5 of the gray values. Therefore storage of up to a pixel 8. If each pixel with the largest storage capacity of 8-bit, the total storage space for 8m ^ 2. In order to reduce storage space, and we will use variable-length model (variable bit scheme), that is different with different pixel median storage. Pixel values of 0 and 1 and only a storage space; The value of 2,3 required two; Value 4,5,6 and 7 of the required three; Analogy.