qt的学习笔记，从简单的hello qt，连接信号，对话框，菜单和工具条。。。到2D和3D图形系统，opengl调用，非常实用...

moto手机大多是基于linux系统，这是著名的showQ系列源代码，共有8种常用界面，对话框，输入框，ZN5 E8 适用！要先有SDK哦-moto phones are mostly based on linux system, which is the famous showQ series of source code, a total of eight kinds of commonly used interfaces, dialog box, input box, ZN5 E8 apply! Oh, must first have a SDK

Linux 基本操作指令-2-basic Linux operating instructions-2

linux 内核调试.rar linux 内核调试.rar-linux kernel debugger. rar linux kernel debugger. rar

实现软盘引导的编码，并在电脑屏幕上显示自己喜欢的消息-achieve floppy guide coding, and on the computer screen to show their favorite news

Linux下的.wav文件播放示例，装了QT的话先#qmake -project生成工程文件pcm.pro，然后 #qmake pcm.pro生成Makefile，然后 #make 最后 #./pcm 执行 注意代码里面包括要播放的.wav文件的路径-Linux under. Wav file playback example, QT installed, then the first# Qmake-project to generate engineering documents pcm.pro, and then# Qmake pcm.pro generated Makefile, then# Make the final#./Pcm attention to the implementation of the code inside the including the need to play. wav file path

一个网络和单机的麻将游戏源码-network and a single source of mahjong game

Learn how to build a custom Linux® distribution to use in an embedded environment, in this case to drive a Technologic Systems TS-7800 single-board computer. In this tutorial, you learn about cross-compiling, the boot loader, file systems, the root file system, disk images, and the boot process, all with respect to the decisions you make as you re building the system and creating the distribution.

编写一个函数，输入n为偶数时，调用函数求1/2+1/4+…+1/n,当输入n为奇数时，调用函数 　　　1/1+1/3+...+1/n(利用指针函数) -The preparation of a function, type n is an even number, the call Function 1/2+ 1/4+ ...+ 1/n, when n is odd input, call function 1/1+ 1/3+ ...+ 1/n (using indicator functions)

mpeg 解复用-mpeg demultiplexing

该模拟的UNIX文件系统应该有以下功能： 多级目录的结构，第一目录为用户名，其余的为它的子目录； 多用户的功能，有8个用户使用同一块数据区； 具有用户登录和注册的功能，如果用户没有用户名和密码就应该注册，如果有了用户名和密码就应该登陆； -simulation of the UNIX file system should have the following features : multi-level directory structure, the first directory to the user name, the rest are in a subdirectory; Multi-user functions, eight users with a data area; With user login and registration functions, if users do not have a user name and secret the codes would be registered, if we have a user name and password should landing;