C++ Builder开发者的很好的参考资料

poj典型题目解题思路详解 包含源代码和解题时应注意的问题及题目陷阱设计分析-POJ typical Oklahoma Elaborates on topics include source code and they should pay attention to solving the problems and pitfalls topic Design Analysis

对C/C++指针进行详细介绍与分析，并且还有C/C++变成规范-Pairs of C/C++ pointers to conduct a detailed introduction and analysis, and there are C/C++ into a standard

c++高手学习必备,c++学习者的有利帮手,快下哦-It s necessary for C++ master, good help for C++ learner.Down it quickly!

testadddll运用DLL实现最简单的加法计算器-testadddll the use of DLL to achieve the most simple addition calculator

编译原理小程序 有点小问题 源程序文件内容如下： main() { int a, b a = 10 b = a + 20 } 要求输出如下： (2，”main”) (5，”（”） (5，”)”) (5，”{“} (1，”int”) (2，”a”) (5，”,”) (2，”b”) (5，” ”) (2，”a”) (4，”=”) (3，10) (5，” ”) (2，”b”) (4，”=”) (2，”a”) (4，”+”) (3，20) (5，” ”) (5，”)”)-Compiler Principle small programs have a small problem source files as follows : main () (int a, b a = b = a 10 20) output requirements are as follows : (2, "main") (5 ,"(") (5, " ) ") (5 ,"{"} (1," int ") (2," a ") (5 ,",") (2," b ") (5," ") (2," a " ) (4 ,"=") (3,10) (5, "") (2, "b") (4 ,"=") (2, "a") (4, "") (3,20 ) (5, "") (5 ,")")

VC++实现的一个查看定时器的类，非常好-VC++ Timer to achieve a view of the class, very good

给定N个大小不等的圆c1,c2,…,cn，现要将这N个圆排进一个矩形框中，且要求各圆与矩形框的底边相切。圆排列问题要求从N个圆的所有排列中找出有最小长度的圆排列。-given N ranging from the size of the circle c1, c2, ..., cn, when it is 000 yen N discharged into a rectangular box, demanding the rectangular box with a round of the hemline tangent. Yuan with the problem demands from the N-round identify all with a minimum length of the round with.

tick tack toe，是一种游戏，用C++语言在Windows

CRC编码算法，用VC实现-CRC coding algorithm, with VC

vc ++ 6.0 教程，详细介绍vc，入门级的选择-vc++ 6.0 tutorial, detailing vc, entry-level choice