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这是一个支持带e符号(如
这是一个支持带e符号(如-12E4)的数字编辑控制-This a support with e symbols (eg- 12E4), the number of editorial control
- 2022-07-08 01:03:29下载
- 积分:1
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A small program on the FDTD in fortran90
一个关于FDTD的三维fortran90小程序.-A small program on the FDTD in fortran90
- 2022-03-13 08:09:11下载
- 积分:1
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GNU Privacy Guard, a tool to encrypt files (e.g. for use as email attachments) w...
GNU Privacy Guard, a tool to encrypt files (e.g. for use as email attachments) with a drag-and-drop interface. Just drop files onto this application and they will be encrypted as self-decrypting EXE files, which will regenerate the original file when executed if you can supply the encryption passphrase. The source code (for Borland C++ Builder) is included
- 2022-03-25 01:06:06下载
- 积分:1
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simple dice game,you can slip it when you need!
simple dice game,you can slip it when you need!-simple dice game, you can slip it when you need!
- 2022-03-17 22:48:55下载
- 积分:1
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题目:企业发放的奖金根据利润提成。利润(I)低于或等于10万元时,奖金可提10%;利润高于10万元,低于20万元时,低于10万元的部分按10%提成,高于10万元...
题目:企业发放的奖金根据利润提成。利润(I)低于或等于10万元时,奖金可提10%;利润高于10万元,低于20万元时,低于10万元的部分按10%提成,高于10万元的部分,可可提成7.5%;20万到40万之间时,高于20万元的部分,可提成5%;40万到60万之间时高于40万元的部分,可提成3%;60万到100万之间时,高于60万元的部分,可提成1.5%,高于100万元时,超过100万元的部分按1%提成,从键盘输入当月利润I,求应发放奖金总数?
1.程序分析:请利用数轴来分界,定位。注意定义时需把奖金定义成长整型。 -Title: Enterprise of the bonus payment of royalty under the profit. Profit (I) less than or equal to 10 million, prize money will be provided as 10 profits exceeding 10 million, less than 20 million, less than 10 million part of royalty by 10, higher than 100,000 yuan part of the cocoa percentage, 7.5 200000-400000 between, more than 20 million parts, may deduct a percentage of 5 400000-600000 between more than 40 million parts, may deduct a percentage of 3 600000-1000000 between, more than 60 million of the royalty to 1.5, above 100 million, over 100 million parts by 1 percent royalty, from the keyboard input month profit I, Qiu-Ying The total number of bonuses? 1. Program analysis: Please use a few axes to boundarie
- 2022-05-26 23:48:27下载
- 积分:1
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VC++调Matlab的简易程序,调出Matlab的figure图
VC++调Matlab的简易程序,调出Matlab的figure图-VC++ tune simple Matlab program, bring up Matlab" s figure diagram
- 2022-01-28 08:21:20下载
- 积分:1
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pacman 搜索 python
人工智能作业......
小游戏pacman......
搜索算法,用python完成......
DFS,深度优先搜索
BFS,广度优先搜索
统一的成本,
启发式算法。。。
1.在 search.py 中的 depthFirstSearch 函数中实现深度优先搜索 (DFS) 算法。若要使您的算法完成,写 DFS 的图搜索版本,
从而避免扩大任何已经了的状态
2.在 search.py 中的 breadthFirstSearch 函数中实现的广度优先搜索 (BFS) 算法。再次,写图搜索算法,可避免扩大任何
已经访问状态。测试你的代码相同的方式,你做为深度优先搜索。
3.在 search.py 中的 uniformCostSearch 函数中实现统一成本图搜索算法。
4.实现 A * 图搜索空函数 aStarSearch 在 search.py 中。A * 采用启发式函数作为参数。启发式带两个参数: 在搜索问题
请点击左侧文件开始预览 !预览只提供20%的代码片段,完整代码需下载后查看 加载中 侵权举报
- 2022-02-05 02:15:14下载
- 积分:1
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图像直方图,均衡化直方图。
图像直方图,均衡化直方图。-image histogram, histogram equalization.
- 2023-08-28 15:05:03下载
- 积分:1
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音频解码器源代码
VC环境下的音频解码源代码,流程非常详细,绝对正确-VC environment audio decoder source code
- 2023-01-11 03:35:03下载
- 积分:1
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windows procedure Winston Installer Version 2.15 Copyright? 1992,1993 DSI
windows 程序Winston Installer
Version 2.15
Copyright ?1992,1993 DSI-windows procedure Winston Installer Version 2.15 Copyright? 1992,1993 DSI
- 2022-03-15 03:04:01下载
- 积分:1