代码和说明,

这是一篇万方数据库上的小论文，有关H.264编码器设计和实现。-This is a WanFangDATA the small papers, the design and implementation of H.264 encoder.

VC++与Matlab混合编程的快速实现。给大家学习这两个工具的启发-VC++ and Matlab programming Fast Implementation of Hybrid. For everyone to learn from the inspiration of these two tools

windows核心编程图书。非常详细的描述了windows编程的原理。-windows core programming books. Very detailed description of the principle of windows programming.

这是当初买FPGA板子附带的verlog教程，感觉写的通俗易懂，希望对大家有用-This is the first place to buy FPGA board attached to verlog tutorial, written in easy to understand the feeling, everybody would like to be useful

VC六个游戏编程，里面包含七个小游戏编译程序，本书很容易理解，会是你入门的好帮手

struts快速入门文章，收集的一些有关STRUTSstruts快速入门的文章，与大家共享-struts Quick Start article, the collection STRUTSstruts some of the rapid entry of articles and share

舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮舞曲。设计要求：模拟上述舞伴系统，并能计算对于任何男士A和女士B在哪一轮舞曲中的k次跳舞？ -Question assumes that a dance partner, the men line up a team, ladies and line up a team. Dancing began, followed by men" s and women" s team from the team dubbed the first one from each partner. If the initial number of teams is not the same, then the longer of that team who is not waiting for the next round of the dance pairs. Design requirements: Analog the partner system, and can calculate for any men" s A and women dance in B in which a k-dance?

RS232串口通讯模块

C语言库函数源码 拿来分享 希望对大家有用-C library function code I hope to it will give you help

JSF自定义组件的简单创建，其中有简单的例子可以参考。-JSF custom components to create a simple, including a simple example for reference.