jsp管理系统

游戏修改器 游戏修改器 -Play games Modifier Modifier Modifier games

素数生成算法，用于生成公共密钥，CA分配公共密钥。-prime number generation algorithm used to generate the public key, CA public key distribution.

rc5 and des encryption and decryption

用JAVA做的模拟电梯的程序,是自己做的- Simulation elevator procedure does which with JAVA, is oneself does

详细的AESRSASHA1实现原理，其中RSA中内容自建的大书包。-Detailed AESRSASHA1 Principle, in which the contents of self-RSA big bags.

线性移位寄存器是流密码的重要组成部分，该程序就是实现该方法。- The linearity shift register is the stream cipher important constituent, this procedure realizes this method.

这是MD5算法的 Asm 实现，代码效率高，-This is the MD5 algorithm Asm implementation, code efficiency,

here is code about aes code for u to understand what the aes is talking about-here is code about aes code for u to understand what the aes is talking about..........

超级兔子有一个文件加密功能，文件被加密以后，打开该文件时，回转到控制面板，可是我们忘了密码怎么办呢？这里提供了一个简单方法-Super rabbit has a file encryption, file is encrypted then, open the file, back to the control panel, but we forget the password how to do? Here provides a simple way

笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中，我们进行语音或者业务信道解调时，都会遇到CRC的求解。通常在硬件DSP实现时，特别是40位CRC求解时候，由于生成多项式有41项，DSP最大一次能处理40位，所以使用单个寄存器会遇到一些困难，那么以下这个程序将会解决这一困难（这是针对定点DSP、C55xx的编程实现方法）。-The author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods).