vs Ping LAN messaging and procedures. Rar

浙大网络编程课全套资料，其中包括课件，相关软件，八个编程例子，课后作业，实验与应用等五个部分。希望对大家学习网络编程有所帮助。开发环境为VC 6++ MFC-Zheda a full set of network programming classes, including courseware and related software, eight examples of programming, after-school work, experiments and applications of five parts. Everyone would like to learn network programming help. Development environment for VC 6++ MFC

简单的Socket类，通过简单修改可以在UIIX/LINUX平台上使用-simple Socket class, through simple changes in UIIX/Linux platform use

宽带运营支撑系统采集模块，客户登录，服务器对登录信息进行采集-Broadband Operational Support System acquisition module, customers log on, server log information collected on

网上商城系统，通过ASP实现。通过修改少量代码即可以运行，商家绝密版！一定要下载哦-Online Mall system, achieved through the ASP. By modifying a small amount of code that can run, businesses, top-secret version! Oh, must be downloaded

不错的程序。可以实现网上购物的功能，代码简单实用-good procedures. Shopping online can realize the function, code simple and practical

一个较老的微软公司的NDIS驱动程序-A older Ndis driver of Microsoft Company

WinSocket 编程指南，对编程人员有一定的帮助-Winsocket Programming Guide, the programming staff can help

RPC的使用,远程方法调用,很好的,却-The use of RPC, Remote Method Invocation, very good, but

使用c++语言编程，通过对计算机注册表的修改，对windows的桌面进行个性化的设置。本程序可用于学习c++语言编写注册表的方法，对于初学者有一定的帮助。

1-持续CSMA协议下，当一个用户要发送数据时，它首先侦听信道，看是否有其他站点在传送。如果信道忙，就持续等待直到信道空闲时，便将数据送出。若发生冲突，就等待一个随机长的时间，然后重新侦听。 对于这种协议，先考虑当前帧i时的前一帧时i-1，得到前一帧时的最后一帧frame0（相对时间最大的帧）的相对时间dt0，然后再在当前帧时查看有哪些帧的相对时间会小于dt0，这些帧若是发送就会与frame0发生冲突，所以这些帧就进入持续等待状态，这些帧并没有发送。再考虑当前帧余下的帧（dt > dt0），它们中的第一帧侦听到信道处于空闲状态，所以就发送，而其他的帧由于第一帧的发送又处于等待状态。若有大于或等于2个帧的相对时间相等，且它们又同时侦听到信道空闲时，就会同时发送而导致冲突，冲突发生后的处理方法同上两个协议的一样。 -1- CSMA continued under the agreement, when a user to send data, it first interception Channel to see if there are other sites in transmission. If Channel busy, continuing to wait until the idle channel, and put more information out. If there is conflict, it is a long wait for a random time, then re-interception. Such agreements, to consider the current frame i am one of the former when i-1, be a time before the final one frame0 (relative to the time frame) the relative dt0 time, and then when the current frame to detect what the relative time frame will be less than dt0, these frames will be sent if and frame0 conflict, th