智能网络办公系统，OA，文档管理，邮件管理等

atmega8+vs1003B+sdcard 制作的mp3模块，有原理图和程序，icc6.31a软件编译的工程，希望对大家有益

迷宫求解一般采用“穷举法”，逐一沿顺时针方向查找相邻块（一共四块－东(右)、南(下)，西(左)、北(上)）是否可通，即该相邻块既是通道块，且不在当前路径上。用一个栈来记录已走过的路径栈是限定仅在表尾(top)进行插入或删除操作的线性表。(Maze solving generally use the " exhaustive" one by one to find adjacent blocks in a clockwise direction (a total of four- East (right), South (down), West (left), North (on)) whether to pass, that the both channel blocks adjacent blocks, and not in the current path. Use a stack to record the path traversed stack is limited only in the tail (top) to insert or delete a linear form.)

实现ads1110电压模数转换和lcd1602显示以及电阻测量(ADS1110 voltage analog-to-digital conversion and LCD1602 display and resistance measurement)

面向对象大作业，C++实现校园卡乘车系统，教师、职工和学生分别持有不同卡种，含有不同的乘车收费免费规则，没有加入数据库，只作简单的I/O文本文件读写。

图像处理器：灰度变换、中值滤波、膨胀、腐蚀、傅里叶变换、仿射变换、油画效果、图片保存等

ansys 求解桥梁结构弯矩响线的命令流，非常实用(ansys solving the stream of the bridge structure bending ring line command is very useful)

sso 另外一个sample程序 c#开发 openid(sso another sample program c# development openid)

vc++和matlab混合编程，本书提供vc++和matlab混合编程的方法(vc mixed and Matlab programming, this book provides vc mixed and Matlab programming method)

AVR system on ATMEGA 31 bit

捕鱼和分鱼；用逆推法求EX=1+x+x.x/2!+x.x.x/3!......的值；找出一个二维数组的“鞍点”(fishing and the fish; Backstepping method used for EX x.x x = 1/2! x.x.x/3 !...... value; find a two-dimensional array of the "saddle")