这是一个时间陷阱问题,不小心的话就会GAME OVER哦!哈哈!就看你的啦!...

用汇编实现加法个可的年发个的就发个 个 个的发个的发个的发和的发和个的发个的个和的发-additive used to achieve a compilation of the year could be made on the fat out of 000-- the fat out of the fat and out of the fat and out of the 000 and 000 of the fat

控制LED慢慢变亮和慢慢变暗的一个汇编程序.初学者可以多分析一下,从而能学到一些编程方法和思路-control LED change slowly and gradually darken-a compilation of the procedure. Beginners can analyze, It will be able to learn some programming methods and ideas

用汇编语言写的，可以实现较大数的加法运算，带回显得显示结果-Written using assembly language, you can achieve a larger number of addition operations, it is back to show the results of

手把手叫你学单片机，这是里面的源代码，很适合初学者快速上手51单片机的资料-You to learn hands-called single-chip, which is inside the source code, it is suitable for beginners quick start 51 SCM information

汇编速查手册..是初学者的实用工具-Info compilation manual .. is a practical tool for beginners ...

程序运行后,在屏幕上接收键盘输入的字符串,然后存如某个指定的内存单元里-Program running on the screen to receive keyboard input string, and then deposit such as a designated memory cell where

通过用汇编语言编写液晶屏幕显示程序,连接左右液晶地址口和数据口,通过开关来来控制点亮和点灭.点亮开关则显示欢度佳节4个字样,点灭则屏幕是空.-Through the use of assembly language procedures for the preparation of liquid crystal display, LCD address to connect around the mouth and data port, through the switch to control light and point out. Lit switches show to celebrate the festive season four words, point out the screen is empty.

汇编程序的查询手册，还是蛮好用的。汇编程序的查询手册。-Assembler manual query, or just fine useful.

4相6线步进电机程序，用于测试步进电机，驱动采用反向驱动-4-phase stepper motor 6-line procedures for testing stepper motor, drive the use of reverse drive

学生成绩核算系统的设计与实现（25） 要求：（1）按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 （2）三个成绩对总评成绩的百分比被定义为常数，各占总成绩的30 、30 和40 。 （3）计算每位学生的总评成绩。 （4）计算该班级本课程的总平均成绩。 （5）计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优，89-80为良，79-70为中，69-60为及格，60分以下为不及格。 （6）按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop