一个加法练习的程序。。针对小学生做的。带家教的时候做的。很方便学习...

这是一个简单的迷宫程序，我花费了一天的时间写的-This a simple maze procedure, I spent a day of time to write!

这个机器人完全模拟人的操作，喜欢的朋友一起研究。 文件为jar包，内容完整。-complete simulation of the robot"s operation, like the friends together. Documents jar package, the content is complete.

它是循环链表节点。与节点，可以添加数据。通过使用这我们可以能够创建节点删除一个节点并修改的值

使用JSTL编写注册用户管理系统，可以实现注册用户的增删改功能-used textbook prepared registered user management system, users can achieve additions, deletions and change function

this a prolog implementation to solve a single maze-this is a prolog implementation to solve a single maze

我们将用程序来模拟传统的龟兔赛跑问题。我们将采用随机数生成的方法开发这一问题的仿真程序。 再比赛中共设了70个点，每个点代表比赛跑道可能的一个位置。乌龟和兔从第一个点出发，终点是在第70个点上。 时钟按秒来数计。随着时钟的转动，程序能够根据下述规则来调节乌龟和兔子的位置。动物 跑动类型 占用时间 跑动量乌龟 快走 50% 向右3个点 后滑 20% 向左6个点 慢走 30% 向右1个点兔子 睡觉 20% 不动 大后滑 20% 向右9 个点 快走 10% 向左12个点 小步跳 30% 向右1个点 慢后滑 20% 向左两个点 -procedures we will use to simulate the traditional hand problems. We will adopt the random number generator of the development of the simulation program. Another winner set up 70 points, each point represents the runway competition of a possible location. The turtle and a rabbit from the starting point and finish in the first 70 points. According to the clock to a few seconds of dollars. As the clock turned to procedures under the following rules to regulate turtle and the rabbit"s location. Running types of animals occupying volume running time 50% of turtles to leave three points right after sliding 20% six points left walking 30% a point right rabbits sleep 20% Fixed After a 20% slide right nine points to leave 10% left

详细的介绍了93系列EEPROM 原理， 编程方法，应用， 例子。 非常有用！-detailed account of the serial EEPROM of 93 principles, programming, application examples. Very useful!

基于FPGA的16点FFT快速傅立叶变换的Verilog源代码。-the FFT implement of Verilog based on FPGA

双 极 2 相 步 进 电 机 驱 动-bipolar two phase stepper motor driver.

Linux PNP-ISA 1.0规范,嵌入式的兄弟也许用得着-Linux PNP- ISA 1.0 norms, the brothers Embedded perhaps worthwhile