IC卡读写软件

八数码游戏的源代码，可自动生成初始状态，搜寻路径达到目标状态-eight digital game"s source code can be automatically generated initial state, the search path to achieve target state

mfcc c++ code This program is free software you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation either version 2 * of the License, or (at your option) any later version. -mfcc c++ code This program is free software you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation either version 2 * of the License, or (at your option) any later version.

〈EVC高级编程及其应用开发（Embedded Visual C++嵌入式编程）〉书上的源代码 全书共分13章，分别为WinCE及EVC概述、图形编程、对话框控件、进程、线程、文件和注册表、WinCE基础数据库编程、WinCE扩展数据库编程、通讯编程、UDP和PING编程、TCP编程、DLL编程以及COM编程。读者在具有一定C抖和WinCE知识的基础上，通过本书的学习，可以快速提高WinCE的编程能力和实际开发水平。- book on the source code book is divided into 13 chapters, each of WinCE and EVC outlined, graphics programming, dialog controls, processes, threads, documents and the registry, WinCE based database programming, WinCE expanded database programming, communications programming, and PING programming UDP, TCP programming, programming and COM DLL programming. Readers with certain C jerk and WinCE knowledge, based on the book learning, can rapidly improve WinCE programming capacity and the actual level of development.

程序 stleft (var vobn，x1s，y1s，x、 y、 plx x 1，x 2，y1，y2:integer） ； 开始 案例 vobn 的 9,8,12,17,13,19,16,5,15： 开始 y1s： = y1 + y; x1s： = x 1 + x ； 如果 vobn = 8 然后 y1s： = y1s + 10 ； 如果 vobn = 13 然后 y1s： = y1s + 20 ； 结束 ； 3、 10： 开始 y1s： = y2 + y; x1s： = x 2 + x ； 结束 ； 2，6、 18： 开始

用C++实现的队列数据结构。对数据结构和算法的初学者是很好的学习材料。-The file is about queue data structur.It is implemented with C++ language.

限制程序对网络访问-procedures to restrict network access

ocr接口可识别英文数字，可以方便的加入你的工程中  

制作线程竞赛的实例。运行该程序时，能够产生一个带有三个跑道的界面，有三个黄色的圆形在竞赛谁跑得最快，到达终点后，程序结束运行。-threads contest produced examples. Run this program, to have a runway with three interfaces, three yellow circle in the competition, who ran the fastest arrival, the end of the program running.

how 2 multiply matrix-how 2 multiply matrix??

this a advertising agency system-this is a advertising agency system