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Order to map any of the distance between two nodes, (2) with two
求图的任两结点间的距离,(2) 用二维数组存放C和A ,C是原成本矩阵,A 是求出的距离矩阵
(3) 算法采用三重循环,其中最外层的循环变量必须代表中间结点,中层的循环变量代表头结点而内层循环变量代表尾结点。
(4) 试着把三层循环变量的顺序作些改变,最外层的循环变量仍代表中间结点,而中层循环变量代表尾结点,内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同
(5) 显示结果要清晰易懂
(6) 本题运行结果
-Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q
- 2022-04-20 12:55:19下载
- 积分:1
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货郎担分枝限界图形演示
问题描述:某售货员要到若干城市去推销商品,已知各城市之间的路程(或旅费)。他要选定一条从驻地出发,经过每个城市一遍,最后回到驻地的路...
货郎担分枝限界图形演示
问题描述:某售货员要到若干城市去推销商品,已知各城市之间的路程(或旅费)。他要选定一条从驻地出发,经过每个城市一遍,最后回到驻地的路线,使总的路程(或旅费)最小。-traveling salesman Branch and Bound graphic demonstration Problem description : A salesman to a number of cities to sell commodities, the known distance between cities (or travel). He selected a departure from the resident, after each city again, the last resident to return to the line, making the total distance (or travel) is the smallest.
- 2022-01-25 16:17:23下载
- 积分:1
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R树与B树的混合树,在这个程序里面可以直接用R树和B树
R树与B树的混合树,在这个程序里面可以直接用R树和B树-R and B-tree tree of mixed tree, in the inside can directly with the R and B-tree tree
- 2022-07-17 09:31:58下载
- 积分:1
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个人课程设计管理系统,写在一个宿舍的全源码…
个人课程设计写的一个宿舍管理系统的全部源代码-Personal curriculum design management system written in a dormitory full source code
- 2022-01-25 16:20:34下载
- 积分:1
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矩阵连乘问题 对多个矩阵连乘时 的消耗进行分析
矩阵连乘问题 对多个矩阵连乘时 的消耗进行分析-matrix continually multiply problems for a number of matrix continually multiply the consumption analysis
- 2023-07-23 09:15:03下载
- 积分:1
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三道几何题:hdu 1007、hdu 2289、poj 3714
三道几何题:hdu 1007、hdu 2289、poj 3714-Three geometry question: hdu 1007, hdu 2289, poj 3714
- 2022-02-15 06:47:15下载
- 积分:1
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思想很简单,就是一个循环链表
但要说明的是:我之所以用clist(1)来初始化,主要是我刚开始编的时候没打算解决约瑟夫环,只是想编一个带表头的循环链表...
思想很简单,就是一个循环链表
但要说明的是:我之所以用clist(1)来初始化,主要是我刚开始编的时候没打算解决约瑟夫环,只是想编一个带表头的循环链表,然后我用从这个程序改过来的,所以代码可以进一步优化。-Thinking is very simple, that is, a cycle list but would like to note is: I use clist (1) to initialize, mainly because I had just started when Joseph did not intend to resolve the ring, just want to provision a table with the head circulation list, and then I used to come from this process, so the code can be further optimized.
- 2022-09-15 15:25:03下载
- 积分:1
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提醒的例子,大家可以去看看
提醒的例子,大家可以去看看 -Remind example, we can go and see
- 2022-07-05 09:16:47下载
- 积分:1
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float型而二叉树的创建及遍历
#include
#include
struct BiTNode //定义二叉树结构体
{
float data;
struct BiTNode *lchild;
struct BiTNode *rchild;
};
//二叉树创建函数
struct BiTNode *CreateTree(float *preorder,float *inorder,int lenth)
{
float *p,*q;
- 2022-12-24 11:10:03下载
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采用链式存储结构设计广义表,实现以下操作:创建广义表,取广义表的表头元素和表尾元素 求广义表的深度...
采用链式存储结构设计广义表,实现以下操作:创建广义表,取广义表的表头元素和表尾元素 求广义表的深度-Chain store use of the structural design of the generalized form, realize the following: create a generalized form, check the generalized table header elements and table elements for the end of the depth of the generalized form
- 2023-06-16 10:10:04下载
- 积分:1