C语言写的俄罗斯方块程序 其中的主要逻辑有： （1）由于c的随机性函数不好，所以每次游戏开始根据bios时间设置种子。 （2）得分越高，方块下降速度

实现图书查询等功能，可以帮助新的同学完成毕业的课程设计-Book Search features to achieve, you can help the new students to complete graduate course design

求两位数字的加，减，乘，除，虽然程序简单 但是写的很好，可以参考一下。8086测试通过-seeking two figures, plus or minus, multiplication and addition, although the procedures are simple but very well written and can reference. The test 8086

汇编写的非压缩BCD码减法。实现两个非压缩BCD码在机器语言中的减法。但未实现输入-compilation write uncompressed BCD subtraction. Achieving two non-compressed BCD in the machine language of subtraction. But to achieve the importation

获取内核内存地址的汇编代码。-access to the kernel memory address compiled code.

看雪软件安全http:www.pediy.com 上 翻译的opcode结构的文章 对学习反编译很有用处-See the snow on the translation of software security http:www.pediy.com the opcode structure of the article on learning useful decompile

多位的加减运算，允许有负数.-number of addition and subtraction operations and allow a negative.

,片选接到p1.5 复位端 p1.4 中断端接到 int0 82c250工作在斜率模式下 ，RS 接51k电阻到地。 2，SJA1000与82C250的接口，逻辑上为SJA1000输出0（显性位），表现为低点平输出给82C250，则82C250输出 差分的低电平。SJA1000输出1（隐性位），表现为高电平或悬空输出给82C250，则82C250输出悬空状态。 3,周立功的中SJA_BCANCONF.ASM中对输出控制寄存器 的TX0的输出 极性的位的定义不对。 还有里面定义有接收错误标志码，不知道何时用。-, The election received a P1.5-chip client p1.4 interrupt reset int0 82c250 client received in the slope mode, RS then 51k resistor to ground. 2, SJA1000 with the 82C250 interface, logic for SJA1000 Output 0 (dominant bit), showing low level output to the 82C250, while the low-level differential output 82C250. SJA1000 Output 1 (recessive), and the performance of the output is high or left vacant to the 82C250, the vacant state 82C250 output. 3, Zhou Ligong in the SJA_BCANCONF.ASM of output control register TX0 output polarity bit the definition of wrong. Inside the definition also has to receive error flag code, I do not know when to use.

在屏幕上用黄颜色显示天堂两个字并且经过一定得时间向右平移一段距离。-Yellow on the screen with color display and after the word heaven must have time to shift to the right for some distance.

汇编语言的准备知识- Assembly language preparation knowledge

一个AD9851的驱动。用的并行时序。 现在把程序和电路图发上来，大家帮帮我看看问题出在那里。谢谢了。 要是有做成功的能共享一下电路和程序感激！ main.c -An AD9851 driver. Timing used in parallel. Now that the procedures and schematics hair up, everyone help me to see the problem there. Thank you. If success has to do to share about the circuit and procedures grateful! main.c