实现heap排序的算法，首先把Heap建立起来，然后通过对Heap的根节点来找出当前最小的节点，依次就可以实现排序了。...

精心链表操作,对单向双向的链表操用实例，精当-carefully chain operation, a one-way pairs two-way linked list speaks examples of elder

SPLASH is a c++ class library that implements many of the Perl constructs and data types, including extensive regex regular expression pattern matching. For those not familiar with Perl, it is an excellent scripting language by Larry Wall and is available for most platforms. This Class library provides List, String, Regular Expression, and text manipulation handling capabilities based on those provided in Perl

基于SDL的关于二叉树计算的源代码，是TXT的一些程序-SDL-based binary tree calculated on the source code, are some of the procedures TXT

随机输入n跳直线 利用增量算法 在一个方块区域内实现他的dcel图 利用opengl把效果图展示出来 -Stochastic input n-hop linear incremental algorithm in a box to use within the region to realize his plan to use opengl to dcel effect diagram displayed

实现构造哈夫曼树的哈夫曼算法。 求解出所构造的哈夫曼 使用树的带权路径长度。 -Huffman tree structure to achieve the Huffman algorithm. Solving the structure of the Huffman tree with the right to use the path length.

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假设一个文件中出现了8种符号S0，SQ，S2，S3，S4，S5，S6，S7，那么每种符号要编码，至少需要3bit。假设编码成000，001， 010，011，100，101，110，111。那么符号序列S0S1S7S0S1S6S2S2S3S4S5S0S0S1编码后变成 000001111000001110010010011100101000000001，共用了42bit。我们发现S0，S1，S2这3个符号出现的频率比较大，其它符号出现的频率比较小，我们采用这样的编码方案：S0到S7的码辽分别01，11，101，0000，0001，0010，0011， 100，那么上述符号序列变成011110001110011101101000000010010010111，共用了39bit。尽管有些码字如 S3，S4，S5，S6变长了(由3位变成4位)，但使用频繁的几个码字如S0，S1变短了，所以实现了压缩。对于上述的编码可能导致解码出现非单值性：比如说，如果S0的码字为01，S2的码字为011，那么当序列中出现011时，你不知道是S0的码字后面跟了个1，还是完整的一个S2的码字。因此，编码必须保证较短的编码决不能是较长编码的前缀。符合这种要求的编码称之为前缀编码。要构造符合这样的二进制编码体系，可以通过二叉树来实现。-Suppose a file appears in eight kinds of symbols S0, SQ, S2, S3, S4, S5, S6, S7, then each symbol to be encoded, at least 3bit. Suppose encoding 000,001, 010,011,100,101,110,111. Then the symbolic sequence S0S1S7S0S1S6S2S2S3S4S5S0S0S1 encoded into 000001111000001110010010011100101000000001, sharing a 42bit. We found that S0, S1, S2 these three symbols the frequency of relatively large, the other symbols the frequency is relatively smal

strassen算法的扩展，可以计算任何偶数阶矩阵的相乘，一般strassen只能计算2的n次方阶（自己编写，英文注释~）-Strassen expansion algorithm can even order any calculation of matrix multiplication, general Strassen only two terms of the n-th-order (to prepare themselves, English Notes ~)

Computes estimates for the number of forests of a graph, input as a 0-1 incidence matrix. Notes: Compile in C++, "g++ -o span_forest span_forest.c". The program does not demand that the matrix is symmetric with 0 diagonal, but uses only the upper triangular part. -Computes estimates for the number of fores ts of a graph. input as a 0-1 incidence matrix. Notes : Compile in C, "g-o span_forest span_forest.c." The program does not demand that the matrix is symmetric wit h 0 diagonal. but uses only the upper triangular part.

在学习堆栈的应用时，有一个很典型的例子，就是火车车厢的重排问题，该程序就是针对这个做了一个简单的MFC模拟程序-in learning the application stack, it is a very typical example is the train compartments, the rearrangement, The procedure is to address this and make a simple MFC simulation program