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VC++ Student Information Management System 1. Remove the " Read Only" a...
VC++学生信息管理系统
1. 去掉“只读”属性。
2. 在SQL Server2000中,附加数据库UGMS。
3. 编译不受源文件位置和数据库位置的影响。即,HMS的整个工程复制到任何地方都可编译。-VC++ Student Information Management System 1. Remove the " Read Only" attribute. 2. In SQL Server2000, the additional database UGMS. 3. Compiled from the source file location and database location of impact. Namely, HMS copy of the entire project can be compiled anywhere.
- 2022-03-01 23:09:17下载
- 积分:1
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模拟电子技术的课件
希望对需要的人会有些帮助
模拟电子技术的课件
希望对需要的人会有些帮助
-Analog electronic technology courseware hope to those who need some help
- 2022-03-21 23:24:42下载
- 积分:1
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电脑可以猜出你心中的牌是什么牌 只需要询问2次,试试吧.
电脑可以猜出你心中的牌是什么牌 只需要询问2次,试试吧.-computer can guess your mind what license plates is only need to ask two times, try playing ......... ..........................
- 2022-01-26 03:19:33下载
- 积分:1
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根据数据库发送条屏数据.根据呼叫发送特定的信息.
根据数据库发送条屏数据.根据呼叫发送特定的信息.-In accordance with Article Send screen data database. According to the call to send a particular message.
- 2023-02-13 05:10:03下载
- 积分:1
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VGA的硬件接口定义,方便大家作为速查资料
VGA的硬件接口定义,方便大家作为速查资料-VGA hardware interface definitions to facilitate information as Info
- 2023-05-31 01:15:03下载
- 积分:1
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ASN1_BER_DER编码子集入门指南,指导asn1的开发
ASN1_BER_DER编码子集入门指南,指导asn1的开发-ASN1_BER_DER coding subset portal guide to the development asn1
- 2022-11-11 03:00:04下载
- 积分:1
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There are a variety of icon, cursor, for many people being developed is a good h...
里面有很多种图标,光标,对很多正在进行开发的人无疑是一个好的帮手啊~!-There are a variety of icon, cursor, for many people being developed is a good helper ah ~!
- 2022-01-28 07:02:33下载
- 积分:1
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Find prime numbers prepared by screening the function: void sieve (bool isPrime...
编写筛选查找素数函数:
void sieve(bool isPrime[], int n)
其中isPrime[ ]为一个布尔型数组,n为数组大小。由于2是第一个素数,
所以设置isPrime[0]和isPrime[1]的值为false,并设置其余的元素初值为true。
然后对从4到n-1的每一个i,判断i是否能够被2整除,如果i能够被2整除,则设置isPrime[i]为false。
对从2到n/2的每一个可能的数值重复以上处理,当操作结束时,所有值为true的isPrime[i]所对应的i就是素数,它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
- 2023-03-02 04:45:03下载
- 积分:1
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这是一个“迷宫”,迷你游戏,移动键盘控制。环境…
这是一个“迷宫”小游戏,键盘控制移动。执行环境为 TC 3.0。-This is a "labyrinth" mini games, mobile keyboard control. The environment for the implementation of TC 3.0.
- 2023-04-10 11:35:03下载
- 积分:1
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拼写检查器
拼写检查-Spelling Checker
- 2022-03-20 05:46:29下载
- 积分:1