进入一个网站，该网站会请您输入姓名，输入完后，该网站就会对您打招呼喔！这程序就是这功能！...

测试串行通讯口的程序,全部源码,共大家下载使用!-serial communication port testing procedures, all of the source code, we were downloading!

demo by N. Sidiropoulos and R. Bro clear all F=5 ％ users I=4 ％ antennas-demo by N. Sidiropoulos and R. Broclear all F = 5 usersI = 4 antennas

网络上少有的MFC Windows程序设计的中文第二版全套，包括每一章节的练习程序的源码-Network, the few MFC Windows program designed to complete the second edition of the Chinese, including the procedures for each of the sections of the source code of practice

流动和传导过程的详细描述，对水流过程，热传导的过程都提出了很好的解决方案，非常适合学习。-Conduction process flow and a detailed description of the current process, the process of heat transfer are put forward a very good solution, is ideal for learning.

很强大的源码JEECMS v2.3.2 Final版-JEECMS v2.3.2 Final

是ISE的中文教程，主要是对初学者演示和展示在XILINX的ISE集成软件环境下，如何用VHDL和原理图的方式进行设计输入，用MOdelsim方针。-ISE is a Chinese course is mainly for beginners and display presentation of the ISE in XILINX Integrated Software environment, how to use VHDL and schematic design entry way, with the principle of MOdelsim.

11e的草案 相信对相关研究人员很有用 如果你在这里搜到了，就下载它吧-11e draft of the relevant researchers believe that useful here if you are found, then download it now

数字系统与VHDL程序设计语言[PPT教程] ， 非常有用． -Digital System Design with VHDL language [PPT Guide], very useful.

linux C编程 参考手册 C语言编程必备-linux C programming language programming an essential reference manual for C

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected