操作系统模拟磁盘调度算法 先进先出 最短优先 扫描算法

以c语言实现内存分配 算法较好-to achieve better memory allocation algorithms

BIOS基本设定练习模拟器-BIOS basic exercises set simulator

protel 　ＤＸＰ　　　　实 例 1-protel 　　ＤＸＰ　　　实 例 1

数值分析课程上机 拉格朗日插值多项式 插值多项式存在唯一性 在次数不超过N的多项式集合Ｈn中　满足条件的插值多项式Ln(x)^Hn 是唯一存在的！ 牛顿插值　三色～-numerical analysis courses on the plane Lagrange polynomial interpolation polynomial interpolation existence and uniqueness to the number not exceeding N polynomial Hn pool to meet the conditions of polynomial interpolation Ln (x) ^ Hn is the only exists! Newton"s three color ~

/*大屏幕显示数字时钟*/ /*要求屏幕按640*480分辩率显示数字时钟，格式为12：18：30，表示12点18分30秒，共8个字符；*/ /*每个字符以80*100点阵显示，记时真确*/-/* Large Screen Display Digital Clock*//* Require the screen by Resolution 640* 480 display digital clock, the format of 12:18:30, 12:18:30, a total of eight characters;*//* Each character with the 80* 100 Lattice revealed that in mind when true* /

这是一个测量频率得程序文档，测量精度高，可测范围宽-This is a measurement of the frequency of a program documentation, measurement and high precision, enable the detection range

某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。-A company to transfer data using public telephones, the data is four integers, in the transmission process is encrypted, encryption rules are as follows: Each figures with five, and then divided by 10 instead of the more than a few numbers, and then The first and fourth exchange, the second and third exchange.

用C++实现LR(0)语法分析 用C++实现LR(0)语法分析-C achieve LR (0) C syntax analysis achieve LR (0) syntax analysis

数据装载监控程序-data loading control procedures

ssd5 Exercise2 的答案 This assessment creates an initial version of the auction project that allows user to register, login, and logout. Registered users can post items (advertisements) for auction.-This assessment creates an initial version of the auction project that allows user to register, login, and logout. Registered users can post items (advertisements) for auction.