C++ class instance of the database code three times, layer upon layer additive

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求图的任两结点间的距离，(2) 用二维数组存放C和A ，C是原成本矩阵，A 是求出的距离矩阵 (3) 算法采用三重循环，其中最外层的循环变量必须代表中间结点，中层的循环变量代表头结点而内层循环变量代表尾结点。 (4) 试着把三层循环变量的顺序作些改变，最外层的循环变量仍代表中间结点，而中层循环变量代表尾结点，内层循环变量代表头结点。把两种做法所得结果作比较,看结果是否相同 (5) 显示结果要清晰易懂 (6) 本题运行结果 -Order to map any of the distance between two nodes, (2) with two-dimensional array of storage C, A, C is the original cost matrix, A is to find the distance matrix (3) The algorithm uses the triple loop, one of the most outer loop variable must be representative of intermediate nodes, the middle loop variable represents the first node and the inner loop variable represents the end nodes. (4) tried to three-loop order of the variables to make some changes, the most outer loop variables still represent intermediate nodes, while the middle loop variable represents the end nodes, the inner loop variable represents the first node. The two approaches to compare the results to see whether the results the same (5) shows the results must be clear and understandable (6) The q

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《数据结构与算法入门导学》 第一章 概论 第二章 线性表 第三章 栈和队列 第四章 串 第五章 多维数组和广义 表 第六章 树 第七章 图 第八章 排序 第九章 查找 第十章 文件-" Introduction to Data Structures and Algorithm Study I." Introduction to Chapter II Chapter III Chapter linear stack and queue Chapter IV Chapter V multi-dimensional array of strings and generalized tree table Chapter VI Chapter VII Chapter VIII of the sort ninth plan Chapter X Chapter document search

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给定n 个整数a ,a , ,an 1 2  组成的序列， a n i | |£ ，1 £ i £ n。如果对于i £ j ，有 0 = å = j k i k a ，则称序列区间i i j a , a , , a +1  为一个零和区间，相应的区间长度为j-i+1。-given n integers a, a, and an 1 2

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