数独游戏C++代码，在VC6.0下运行在控制台上，使用回溯法解决，…

CAIMAN method是一种通过挖掘数据的帽子矩阵的对角信息来实现对数据分组的方法。-The CAIMAN method (Classification And Influence Matrix ANalysis) is a classification method exploiting the properties of the diagonal terms of the influence matrix, also called leverages.

windows下自动靠边的窗口(带讲解)-windows automatically sides of the window (on the band)

很简单 的VB小程序，是本人在学习VB过程中制作的。仅以次献给需要完成作业的同学！-very simple VB small program, I was in the process of learning VB production. Only dedicated to meeting the needs of the students accomplished!

用java做的一个记票系统，可以统计选票，用于选举时用-Using java to do a polling system that can votes for the election when

从RPG MAKER XP中提取的一个简单的ruby脚本解释器。使用方法：在script目录下新建rb文件，在require.rb中增加require。执行game.exe运行脚本。-A simple ruby script interpreter. Usage: In the script directory New rb files, require.rb add require. Implementation of the game.exe to run scripts.

c言语环境下进行 龟兔赛跑 仿真 很有趣的小程序-c language龟兔赛跑simulation environment

VC 操控 IE 的使用方式-VC control the use IE

一个简单的曲线显示例子，祝初学者马达成功。visual c-a simple example of the curve, I wish beginners Motor success. Visual c

网络蚂蚁功能模拟 将不同数据包的信息整合-Functional simulation NetAnts different packets of information integration

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected