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诺基亚6280原厂的图纸
诺基亚6280原厂的图纸-Nokia 6280 original drawings! ! ! ! ! ! ! ! ! ! !
- 2022-06-16 23:49:11下载
- 积分:1
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液晶1602详细中文资料,资源共享,互相帮助
液晶1602详细中文资料,资源共享,互相帮助-1602 Chinese liquid crystal detail information, resource sharing, mutual help
- 2023-05-15 07:30:03下载
- 积分:1
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This the Bluetooth Chat server. The server part runs and establishes connection...
This the Bluetooth Chat server. The server part runs and establishes connection with client-This is the Bluetooth Chat server. The server part runs and establishes connection with client
- 2022-01-26 05:54:58下载
- 积分:1
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网上校园在线考试系统v1.1,校园在线考试…
OnlineExam校园在线考试系统 v1.1,校园在线考试系统 + 后台系统管理,默认的后台数据管理员用户名和密码都是:admin,默认的验证密码都是:firekinger -OnlineExam Campus Online Examination System v1.1, the campus online examination system background systems management, the default background data administrator user name and password are : admin, the default password verification are : firekinger
- 2023-08-15 07:40:04下载
- 积分:1
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此提供一个USB接口的编写源码,提供网友共同参考
此提供一个USB接口的编写源码,提供网友共同参考-here to provide a USB source prepared to provide a common reference Netizen
- 2022-01-26 07:33:24下载
- 积分:1
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AM,FSK,PSK调制,自己修改参数,结果用PCM文件保存,以二进制数据读入...
AM,FSK,PSK调制,自己修改参数,结果用PCM文件保存,以二进制数据读入-modulate:am fsk psk
- 2022-10-04 18:00:03下载
- 积分:1
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字符仿真终端 通过一个MSComm控件,实现串口字符通信功能。
字符仿真终端 通过一个MSComm控件,实现串口字符通信功能。-characters through a terminal simulation MSComm control, Serial characters communications functions.
- 2022-02-16 03:00:49下载
- 积分:1
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《ARM无线通信开发实例》这本书的代码和数据文档
《ARM无线通信开发实例》这本书的代码和数据文档-err
- 2022-08-12 15:50:54下载
- 积分:1
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RFC1050
远程过程调用协议规范
- 2022-06-15 13:28:40下载
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We investigate the case of independent Rayleigh faded paths between antenna elem...
We investigate the case of independent Rayleigh faded paths between antenna elements and find that with
high probability extraordinary capacity is available. Compared to the baseline n = 1 case, which by Shannon’s
classical formula scales as one more bit/cycle for every 3 dB of signaltonoise
ratio (SNR) increase, remarkably
withMEAs, the scaling is almost like n more bits/cycle for each 3 dB increase in SNR. To illustrate how great this
capacity is, even for small n, take the cases n = 2, 4 and 16 at an average received SNR of 21 dB. For over 99
of the channels the capacity is about 7, 19 and 88 bits/cycle respectively, while if n = 1 there is only about 1.2
bit/cycle at the 99 level. For say a symbol rate equal to the channel bandwith, since it is the bits/symbol/dimension
that is relevant for signal constellations, these higher capacities are not unreasonable. The 19 bits/cycle for n = 4
amounts to 4.75 bits/symbol/dimension while 88 bits/cycle for n = 16 amounts t
- 2023-04-26 08:00:04下载
- 积分:1