zooming by two method in matlab

xin xi

编译原理的词法分析 改编PL/0成C-compiler tenets of lexical analysis based PL/C 0%

this program is for controling MAC_messages in the simulator, through we can control MAC msges

# 3 节点示例中特设仿真与 AODV # 定义的选项 设置 val(chan) 通道/WirelessChannel; # 通道类型 设置 val(prop) 传播/TwoRayGround; # 电波传播 模型 设置 val(netif) Phy/WirelessPhy; # 网络接口类型 设置 val(mac) Mac/802_11; # MAC 类型 设置 val(ifq) 队列/DropTail/PriQueue; # 接口队列类型 设置的 val(ll) LL; # 链接图层类型 设置 val(ant) 天线/OmniAntenna; # 天线模型 设置的 val(ifqlen) 50 ； # 种中的最大数据包 设置的 val(nn) 3 ； mobilenodes # 人数 设置 val(rp) AODV ； # 路由协议 设置的 val(x) 500 ； # X 维度的地形 设置的 val(y) 400 ； # Y 维度的地形 设置的 val(stop) 150 ； # 时间的仿真结束 设置 ns [新模拟器] 设置 tracefd [打开 simple.tr w] 设置 windowVsTime2 [打开 win.tr w] 设置 namtrace [打开 simwrls.nam w]

五子棋程序，vc开发，双人对战，网络对战-331 procedures, vc development, double the war, the network war

xml实用大全，好不容易弄到的，那出来大家共享了！-xml Utility Daquan, hard to get, and that shared by everyone!

In this talk we will consider two approaches in dealing with the risk of supplier bankruptcy. In the first model, we study the effects of supply disruption risk in a supply chain where one buyer deals with competing risky suppliers who may default during their production lead-times.

超级简单的JVAV ajax 的例子 简单的实现-JVAV ajax simple examples

单循环赛中选手胜负序列求解问题 名称：单循环赛中选手胜负序列求解问题 内容：有n个选手 P 1 ,P 2 ,P 3 ,… ,P n 参加了的单循环赛，每对选手之间非胜即负。现要求求出一个选手序列 P 1 ,P 2 ,P 3 ,… ,P n , 使其满足 P i 胜 P i+ 1 (i=1,… ,n-1) 。 -Single round robin tournament players winning sequence to solve the problem name: the outcome of single round-robin tournament players to solve the problem sequence elements: There are n-player P 1, P 2, P 3, ..., P n participated in a single round-robin between each pair of players Non-win or negative. Players are now required to find a sequence of P 1 " , P 2" , P 3 " , ..., P n" , to meet the P i " W P i+ 1" (i = 1, ..., n-1).

用到，，MFC ，GUI，实现一类过关类的小游戏，，对图形进行处理，-Used,, MFC, GUI, pass the class a class of small game, the graphics processing,