hash算法大全，里面包含了诸如Bernstein s hash，Pearson s Hash，CRC Hashing等流行的算法源码。...

（一）功能要求： （1） 信息维护： 要求：学生信息数据要以文件的形式保存，能实现学生信息数据的维护。此模块包括子模块有：增加学生信息、删除学生信息、修改学生信息 （2） 信息查询：要求：查询时可实现按姓名查询、按学号查询 （3） 成绩统计：要求：A输入任意的一个课程名（如数学）和一个分数段（如60--70），统计出在此分数段的学生情况。 （4） 排序：能对用户指定的任意课程名，按成绩升序或降序排列学生数据并显示排序结果（使用表格的形式显示排序后的输出结果）（使用多种方法排序者，加分） -(1) functional requirements : (a) maintaining information : Request : Student data to information in the form of a document preservation, Students can achieve the maintenance of information and data. This module, including sub-modules are : increased student information, delete information of students, student information changes (2) Information : Request : inquiries can be realized by name inquiries, inquiries by the school, (3) results statistics : requirements : A importation of an arbitrary courses (such as mathematics) and a fraction of the (60-- 70), Statistics from the scores of the students of. (4) Scheduling : users can be designated to the arbitrary courses, and results by ascending or descending student data and sequenci

是用于个人网站建设用的代码, 欢迎使用 用HTML语言编的-personal website for the building code, welcomed the use of the HTML language used series

a transport protocol for real time applications，主要用于音视频、多方会议-a transport protocol for real time applications, mainly used for audio and video, multi-session

这是本科铁道方向课程设计的一个简单的计算程序，用于计算实现轨道“统一公式”-Calculate the formation

java版本的迷宫游戏 也可以自动设置迷宫图案-java version of the maze game can also be automatically set up a maze pattern

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

电力系统分析 随书光盘 源代码， MATLAB编写，有参考价值-CD-ROM with the book Power System Analysis

c语言之函数篇，从基础学起，让你彻底精通c语言的应用。-function of c language,learn form base,lead you to be well up to application of c language

影院售票系统完整源码，图形化售票、退票、预定票直观明了-cinema ticketing system integrity source, graphical tickets, refunds, scheduled votes intuitive understanding

j2me手机游戏代码,内含图片素材和源代码文件-j2me mobile game code, including picture material and source code files