PHP+MYSQL图书后台管理系统

卡通动漫联盟伪静态后台版，如发现程序无法正常使用请到官网下载最新版-Cartoon Animation Alliance version of pseudo-static background, such as the discovery process does not work properly please download the latest version of official website

ANASY焊接模拟实例，对焊接模拟研究分析的人员具有一定的参考意义。- ANSYS simulation of welding

C++实现的复数+_*/运算,自己用了很多年了-C++ complex

一个RPG术语查询器，使用起来挺方便的，希望对大家有用。-an RPG terms for inquiries, quite convenient to use, it may be useful to hope.

利用GOSSIP协议可以实现无线节点之间的路由选择.-use GOSSIP agreement can be achieved between the wireless node routing.

该系统采用B/S架构设计的一个小型的通讯录系统，功能完善，非常实用-The system uses B/S architecture design of a small address book system, fully functional, very practical

压缩包中的例子用非常浅显易懂的方式指明如何使用select,以及select的使用范围-compressed using the example of a very simple and easy way, how to use select, and the use of select

AutoCAD画的三维文件，很不错哦，可以下载后自己参照-Three-dimensional AutoCAD drawing files, oh well, you can download their own reference

开发MySql数据库的最新JDBC驱动。

数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3