C++ primer 5 练习题

说明：  msp430f5529通过输出PWM波控制舵机(Msp430f5529 control steering gear)

说明：  实现 迷宫问题的 A算法 实例。 主要是在人工智能中加深对A算法的新认识(A-STAR block)

Windows 应用程序是靠消息驱动的，在VC中我们通过 Classwizard 可以为某窗口类添加消息处理函数，Classwizard将为你添加消息映射，对于 Windows 消息,生成的消息处理函数重载了基类的虚拟方法。而在C#中如何处理消息呢？本文针对VS.NET 2003 境下的C#简单地介绍 Windows 消息以及自定义消息的处理方法。-Windows applications rely on news-driven, in VC Classwizard we can add a category window message processing function, you will add Classwizard mapping information for Windows news, the news generated processing function overloading of the virtual base class methods. In C# how to handle news? This paper VS.NET 2003 Habitat under the C# Windows to brief definition of news and news from the treatment.

说明：  给定n种物品和一个背包,物品i的重量是Wi,价值是vi,被包容量是C,应该如何选择装入被包的物品,使得装入背包中物品的总价值最大?对于每种物品i,只有两种选择,装入或者不装入. 输入:第一行两个正整数n(物品数)和C(容量) 第二行n个正整数n,表示物品价值 第三行n个正整数n,表示物品重量 输出:第一行表示总价值 第二行n个数(0/1),0表示物品不装入,1表示装入 例如, 输入: 5 10 6 3 5 4 6 2 2 6 5 4 输出 15 1 1 0 0 1 (Species of a given n items and a backpack, the weight of item i is Wi, the value of vi, was packet capacity is C, should be how to choose a package of items to be loaded, the backpack load in the largest total value of goods? For each item i, there are only two options, loaded or not loaded. Input: the first line of the two positive integer n (the number of items) and C (capacity) of the second line of n positive integer n, that the value of the third line of n positive integer n, that the weight of output: the total value of the first line of the second line, said n number of (0/1), 0 that the items do not load, that load 1 for example, enter: 5,106,354,622 6 5 4 output 15 1 1 0 0 1)

msp430f5438系统中文资料(全)(msp430f5438system_Chinese Materials)

makefile编写手册。介绍得比较全面，担前面介绍太多概念，容易失去兴趣。最好还是该跳过时跳过。回头再看(Makefile write manual. To introduce it too is quite comprehensive, bear introduced too much in front of the concept, easy to lose interest. Still had better the jump out of date skip. Back to see )

Huffman编码，使用哈弗曼树生成前缀码，把输入的字符编码并把原字符解码(Huffman code and decode)

利用Arduino实现读取MPU6050的DMP四元数(Arduino MCU reads MPU6050 use a DMP quaternion)

邻带计算，高斯正反算，可以实现测绘系统内简单的转换计算，但是是基于80坐标系统的。(failed to translate)

基于STM32的步进电机控制，含加减速控制方法。考虑了快速加减速时的失步影响。(STM32 based stepping motor control, including acceleration and deceleration control method. Taking into account the rapid acceleration and deceleration when the impact of out of step.)