good sql Manual

本系统为内部系统，帐户由管理员添加、管理； 分为两个组，User组和Boss组。Boss组的帐户可以发广播通知； 任意两个用户间可以互相通信； 数据库接口用DAO，网络通信用 CSocket+CSocketFile；-the system to internal system administrator account by adding, management; Divided into two groups, User Group and the Boss group. Boss Group accounts Broadcasting notice can be issued; Between any two users can communicate with each other; Using DAO Database Interface, Network Communication CSocket CSocketFile;

迷宫的又一解法。该算法简单、实用、可读性强，是学习递归和回溯很好的例子。-maze of another solution. The algorithm is simple, practical and readable study is recursive and backtracking good example.

全国计算机等级考试四级上机的部分练习题，配有我自己写的算法，算法说明和输入输出文件，使实验起来更容易。算法比较简洁易懂，大概有三十题左右（已经去掉了重复和类似的），对考四级的朋友和正在学习C的朋友会有帮助的-National Computer Rank Examination four aircraft on the part Exercises, equipped with my own writing algorithm, the algorithm description and input and output documents, and make it easier to experiment. Algorithms easy to read, there are about 30 or so that (already removed the duplication and similar), the examination of the four friends are learning C and friends can be helpful

在远距离数据通信中，为确保高效而无差错地传送数据，必须对数据进行校验即差错控制。循环冗余校验CRC(Cyclic Redundancy Check/Code)是对一个传送数据块进行校验，是一种高效的差错控制方法。-in long-distance data communication, in order to ensure efficient without error to transmit data, the data must check that the error control. Cyclic Redundancy Check (Cyclic Redundancy Check/Code) is to block transmission of data over a check out, is a highly efficient error control methods.

N皇后的排列树与子集数算法！里面是Cpp的源代码 带注释-N Queen subset of the arrangement of trees and the number of algorithms!

first simple MCF exercise

Coursera课程关于大数据的任务。第一项任务。

数据结构中的二叉树排序问题-data structure, the binary sequencing problem

应用背景在Java数据库连接使用 ；  MySQL；NetBeans，注：这里的学生已经创造了在MySQL数据库MySQL root用户名关键技术MySQL connector.jar文件可从网站：wvw.mysql.comNetBeans IDE  ； ；7.5MySQL 5.51

este archivo permite la creacion de formularios de forma dinamica, ademas obtener su valor y gurdarlo en una base de datos