此软件可以改变oem单调的画面，展现个性自我！

使用pb备份sqlserver数据库-use SQLServer database backup pb

Symbian UIQ的CameraTest.用于高端手机P800、P30、P31等。-CameraTest the Symbian UIQ. For high-end phones P800, P30, agency, etc..

LEON3 SOC environment, PCI bridges.

java编写的拼图游戏源码，编译通过。 对学习JAVA图形编程有益-puzzles prepared by the source, compile. Learning Java graphical programming useful

一些常用的小函数-some frequently used small function

这是一个XML记数器,可用做网页设计中计数器无需解压密码-This is an XML Register and can be used for web design counter without extracting passwords

bayes分类器，本程序根据病人症状可初步诊断疾病-Bayes classifier, this procedure can be based on the patient"s symptoms preliminary diagnosis of diseases

这是一个定轨程序,你可用它计算轨道的位置和速度-satellite orbits determination

数根 数也有根吗？有！数根就是把一个数的各个数位上的值相加，直到得到一个一位数为止。请你编写一个程序来计算任意数N（0≤N≤1000000000000）的根。 输入： 输入有多个案例。每一个案例为一行，每行只有一个整数N。当输入的N是-1时，输入结束。 输出： 每一个案例输出一行。每行只有一个数字，就是N对应的数根。 Sample input 39 -1 Sample output 3-Number of root number also has roots do? There is! The number of roots is to a number of different values on the digital sum until they have been a number of up to one. Please write a program to calculate an arbitrary number N (0 ≤ N ≤ 1000000000000) roots. Input: Enter a number of cases. Each case for the line, each line is only an integer N. When the input of N is-1, the input end. Output: the output line of each case. There is only one number per line, that is, N corresponds to the number of roots. Sample input 39-1 Sample output 3

digital image processing in mathlab