利用现在流行的Ajax技术无刷新动态！一个简单的源…

此代码是用C++编写的，通过建立工程的方法来求一个数的阶乘。适合初学c++者！-This code is used C++ Prepared, through the establishment of engineering methods to seek a number of factorial. Suitable for beginners c++ De!

有一个无穷数列，其通项表示为： a[n]=10*10*... n=0,1,2,3..... 构成了1,10,100,1000... 把它连起来，就成了数串。 判断数串的第i位到底是0还是1.性能要求1s -There is a infinite series, whose general term is expressed as: a [n] = 10* 10*... n = 0,1,2,3 ..... constitute 1,10100,1000 it even ... together, it becomes the number of strings. Determine the number of strings in the end of the first i-bit is 0 or 1. Performance requirements 1s

能够完美显示设备无关位图，运行无误。整体框架注释完整，对图像处理初学者非常有帮助

酒店预订管理系统现在天更受欢迎。客户端预订有需要的留在地球上的某些位置。有两种类型的床，即单或双。和TS价格是不同的。如果客户比价格需要更多的服务是通过增加他们占据了最好的服务。

自动打印HTML文档到默认打印机,不会弹出打印对话框！-Auto-printing HTML documents to the default printer, the Print dialog box will not pop up!

一个WIN32命令行分析程序的源代码.-a command-line analysis of a program"s source code.

吉林大学ACM竞赛试题集锦II，相信对你的编程能力的提高很有帮助，尤其是算法的设计方面-Jilin University ACM Collection II questions, I believe you have the right programming capability to raise helpful, especially to the design algorithm

计算器能够实现基本的四则运算代码看起来简单能适应大多数程序初学者-Calculator to achieve the basic four computing code looks simple procedures to adapt to the majority of beginners

本程序为最短路径的Ｃ源程序，算法简单，执行效率高-the procedures for the shortest path to the C source, the algorithm is simple, high efficiency