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not know
不晓得干嘛用的,主要讲的是这个Function Point Counting Rules-not know-- why use, The main speaker is the Function Point Counting Rules
- 2022-05-13 17:16:00下载
- 积分:1
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Embedded System Overview Part 4, learning embedded system applications based on...
嵌入式系统概述第4部分, 学习嵌入式系统应用的基础, 写的很好,不用买书了.因文件较大,所以分几次传完.-Embedded System Overview Part 4, learning embedded system applications based on the good writing, not the books. for a larger document, in several mass End.
- 2022-05-17 05:01:36下载
- 积分:1
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三篇论文的人脸检测,那些有兴趣的可以看一下,可以的…
三篇关于人脸检测的论文,有意者可以看看,希望有所价值,不要积分-Face detection on the three papers, those who are interested can look at, would like to see the value, not points
- 2022-02-21 21:37:26下载
- 积分:1
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Examples of on
DSP学习板上的例子程序包括
AD转换 CAN总线 SPI SCI -Examples of on-board DSP learning process includes the AD conversion CAN Bus SPI SCI
- 2023-01-20 08:05:04下载
- 积分:1
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used to calculate the sum of two numbers is also test the code HEL
用于计算2个数之和 还有现试HELOO的代码-used to calculate the sum of two numbers is also test the code HEL
- 2022-01-24 18:17:44下载
- 积分:1
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tc 语言教程,pdf 格式,对刚接触的菜鸟非常有用
tc 语言教程,pdf 格式,对刚接触的菜鸟非常有用-tc language tutorials, pdf format, on the rookie刚接触very useful
- 2022-03-16 02:58:35下载
- 积分:1
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快速排序,基本思想:通过一趟排序将待排序记录分割成独立的两部分,其中一部分记录的关键字均比另一部分记录的关键字小,则可分别对这两部分记录继续进行排序,以达到整个...
快速排序,基本思想:通过一趟排序将待排序记录分割成独立的两部分,其中一部分记录的关键字均比另一部分记录的关键字小,则可分别对这两部分记录继续进行排序,以达到整个序列有序。-quick sort, the basic idea : The trip will rank ordering records to be separated into two independent parts, part of the keyword record than another part of the record of the keyword small, will each of the two parts to continue sorting records, in order to achieve an orderly sequence as a whole.
- 2022-02-10 13:56:41下载
- 积分:1
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关于面向构件的软件体系的文档资料
从思想开始更新开发模式...
关于面向构件的软件体系的文档资料
从思想开始更新开发模式-on Component-oriented software system from the Documentation Updates start thinking mode
- 2022-03-22 03:36:25下载
- 积分:1
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bootloader精讲ARM芯片非常详细的注解
bootloader精讲ARM芯片非常详细的注解-Bootloader Intensive ARM chip very detailed notes
- 2022-03-28 13:33:35下载
- 积分:1
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从终端读入要编码的字符串,对所输入的字符串进行频率统计并建立哈夫曼树。
输出每个字符的编码。
根据已有的各个字符的编码,输入一段正确的电文,然后对输入的...
从终端读入要编码的字符串,对所输入的字符串进行频率统计并建立哈夫曼树。
输出每个字符的编码。
根据已有的各个字符的编码,输入一段正确的电文,然后对输入的电文进行译码。-Read from the terminal to encoded string, the string of the input frequency statistics and the establishment of Huffman tree. Output for each character encoding. On the basis of the various character encoding, enter the correct section of the message, and then the input message for decoding.
- 2022-08-11 07:13:19下载
- 积分:1