ne5532放大器的资料，典型电路连接图

美化程序，养成良好的编程习惯，成为真正的编程高手-Landscaping procedures, to develop good programming habits, to become a true master of the programming

标定程序 的 一个新算法，适合初 学者-Calibration procedures of a new algorithm, suitable for beginners

介绍Arcengine二次开发的宝典级电子书-Introduction Arcengine secondary development of the book-class e-book

无线电制作精汇7，里面有电路图和详细的说明。-7 Department of Radio sperm production, which has circuit diagrams and detailed instructions.

Visual Basic.net访问数据库的经典资料-Visual Basic.net classic access the database information

中国联通CDMA定位业务基于用户平面相关设备技术要求v2(050126).doc-China Unicom"s CDMA business positioning based on user plane related equipment technical requirements v2 (050126) . doc

java的异常api,说明了里边的所有异常-java abnormal api on the inside of all abnormal

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matlab常用指令与举例-Matlab commonly used for command and

背包问题动态规划算法JAVA 给定n种物品和一背包。物品i的重量是wi，其价值为vi，背包的容量为c。问应如何选择装入背包中的物品，使得装入背包中物品的总价值最大？ 在选择装入背包的物品时，对每种物品i只有两种选择，即装入背包或不装入背包。不能将物品i装入背包多次，也不能只装入部分的物品i。因此，该问题称为0-1背包问题。-Knapsack problem dynamic programming algorithm for a given n species JAVA goods and one backpack. Item i is the weight of wi, the value for vi, knapsack capacity c. Question should be how to choose the items into the backpack, the backpack into the total value of the largest items? In the selection of the items into the backpack, for each of the items i have only two choices, that is loaded or not loaded backpack backpack. Items should not be many times i load backpack can not only part of the goods loaded i. Therefore, the problem known as the 0-1 knapsack problem.