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简单加密工具原程序
简单加密工具原程序-simple encryption tools original program
- 2022-02-05 20:13:09下载
- 积分:1
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This is a simple program with vb series of the quality factor of the decompositi...
这个是简单的用vb编程编的分解质因数的程序和已经编译了的exe文件-This is a simple program with vb series of the quality factor of the decomposition process and is compiled by the exe files
- 2022-07-25 14:52:54下载
- 积分:1
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16c84
基于16C84做的智能卡程序,可以实现智能设置。-16C84-based smart card to do the procedure, you can realize the smart set.
- 2022-02-06 11:45:31下载
- 积分:1
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enigma3模拟二战的加密算法
ENIGMA3模拟WW II加密算法-ENIGMA3 simulation WW II encryption algorithm
- 2022-02-13 05:10:05下载
- 积分:1
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主要介绍算法的实现方式和流水线实现,而且有详细的原理介绍,推理,源码和仿真结果...
主要介绍算法的实现方式和流水线实现,而且有详细的原理介绍,推理,源码和仿真结果-The main way of introduction Algorithm and pipelining to achieve, but also has a detailed introduction of the principle, reasoning, source code and simulation results
- 2023-09-08 02:55:03下载
- 积分:1
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AES加密源代码实例
AES加密源程序示例-AES encryption source code examples
- 2022-01-26 00:29:39下载
- 积分:1
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用Visual Studio 2003编的文件加密程序,能对文件进行二进制读入,再和密码做异或,保存。版本一...
用Visual Studio 2003编的文件加密程序,能对文件进行二进制读入,再和密码做异或,保存。版本一-Visual Studio 2003 for use of file encryption program, can read a binary file, and then do XOR and password, save. Version 1.0
- 2023-03-19 22:25:03下载
- 积分:1
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JAVA的加密库之一
JAVA的加密库之一-JAVA encryption tank
- 2022-10-11 01:00:02下载
- 积分:1
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大数计算在公钥加密中起到了重要的作用,如何操作大数呢,该程序也许能帮你解决这个问题有所帮助。...
大数计算在公钥加密中起到了重要的作用,如何操作大数呢,该程序也许能帮你解决这个问题有所帮助。-calculated in the end, the public key encryption plays an important role in the operation of large numbers do, the program may be able to help you resolve this problem some help.
- 2023-08-04 22:25:02下载
- 积分:1
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设f(x)= 1×X2 X5 X27,分别尝试写下面的移位寄存器…
设f(x)=1+x+x2+x5+x27,试分别写出实现下列移位寄存器的程序:
以f(x)为联接多项式的DSR;
以f(x)为联接多项式的LFSR。
可供选择的联接多项式:
f1(x)=1+x+x4+x6+x30;
f2(x)=1+ x3+ x31;
f3(x)=1+ x6+ x31;
f4(x)=1+ x7+ x31;
f5(x)=1+ x13+ x31;
-Let f (x) = 1 x x2 x5 x27, respectively try to write the following Shift Register : f (x) connected to the DSR polynomial; f (x) for connectivity polynomial LFSR. Connection options polynomial : f (x) = 1 x x4 x6 x30; F2 (x) = 1 x3 x31; f3 (x) = 1 x6 x31; f4 (x) = 1 x11 x31; f5 (x) = 1 x13 x31;
- 2022-04-07 10:24:13下载
- 积分:1