使用createpolygonrgn和setwindowregion创造奇怪的移动窗口

步进电机控制，能很好地学习单片机控制步进电机的原理及应用。-stepper motor control, can be a good learning SCM stepper motor control and application of the principle.

（1） 系统要买的车票  (2) 在那里你可以选择座位  (3) 分支和巴士 （4） 的次数，是在控制台 （5） 有例外和菜单选项来填补。

1、本程序的作用是进行TEST语言的词法分析。 2、可双击运行后输入文件名，或是在命令提示符下输入test 文件名……，支持多个文件同时进行词法分析。 3、本程序是在VC6.0环境下测试通过，用的是C++语法。当然也有C的语法。 4、本程序留下了很多的接口以待以后的语法分析和语义分析实验时进行扩展。比如已将词法分析结果记入到了一个顺序存储的数据结构中，以待后用。 5、程序扫描处理一部分是经孙悦红老师的示范程序修改而成，（增加了一些功能）其他部分为了适应自己的接口，都是由本人编写。-one, the process is the role of TEST language lexical analysis. 2, double-click operation input file name, or under the command prompt test input file name ... supports multiple documents simultaneously lexical analysis. 3, the procedure was VC6.0 testing environment, using the C syntax. Of course, there are C syntax. 4, the process left a lot of interface to question the future of grammar analysis and semantic analysis experiments expansion. For example, lexical analysis has been credited to a sequence of data storage structures to be used later. 5, the scanning process is handled by the part of teachers Coaldale red model procedures and revisions, (an increase of some function) in order to adapt to other parts of the interface are all prepared b

这个是用C写的哈夫曼编码与解码，起中间数据还用文件显示，以便大家观摩-this is written in C Huffman coding and decoding, starting with intermediate data file, so that we watch

一个获得CPU信息的DLL，可以获得Intel系列芯片的信息，包含范例程序-a CPU access to information DLL, the Intel chips available information, including sample programs

这是一个有关哈夫曼编码的软件,包括哈夫曼的编码和翻译.-A program shows how to implement the Huffman code contains encoding and decoding

BP算法拟合y=abs(sin(x))函数，样本数9对，目标值0.001-BP algorithm fitting y = abs (sin (x)) function, for nine samples right, the target value 0.001

括号匹配 实现三种括号的匹配 不同顺序 不同位置的匹配-Matching brackets brackets matching the achievement of three different positions of different sequence matching

关于猎人过河问题 要解决这个问题就要使过河时载两个过河，返回时尽量只有一个回来。用一个字符串数组来存猎人，狼，羊，白菜；下标依次为0，1，2，3；但他们都有河这边和那边两种状态；为方便则定义一个结构，只含一个int型变量n；当在河这边时n设为0；在河那边时n设为1。由于每次过河与返回都要考虑狼能否吃羊或羊能否吃白菜；则需要一个函数来判断每次选择是否满足条件。-Hunters across the river on the issues to resolve this issue so we should cross the river when the two set out across the river to return to when there is only one back as far as possible. Using a string array to keep hunters, the wolf, sheep, and cabbage subscript followed by 0,1,2,3 but they have a river here and there two states To facilitate the definition of a structure containing only an int variable n When in the river here when n is set to 0 in the river when n is set to one side. Due to cross the river and return each time to consider whether the wolf can eat the sheep吃羊or cabbage you need a function to determine each choose whether or not to meet the conditions.

一个用C++编制的控制仿真程序，效果挺好的 。有兴趣的可以-C compiled a control simulation program, the effect is very good. Interested parties can s