Vovida a VOIP product of the wonderful training manuals detail the H323, SIP, MG...

RFID EPC GEN22.pdf RFID GEN介绍-RFID EPC GEN22.pdf RFID GEN Introduction

数据仓库10-pdf-data warehouse 10-pdf

相对Hibernate和Apache OJB 等“一站式”ORM解决方案而言，ibatis 是一种“半 自动化”的ORM实现。-relative Hibernate and Apache OJB and other "one-stop" ORM solutions, ibatis is a "semi-automated" ORM achieve.

CODEVISION AVR C语言程序设计-CODEVISION AVR C Programming Language

这是一个介绍面向对象方法学的电子书.他详细的介绍了面向对象的特性及思想.是一个能使读者快速学习的资料.-This is an introduction of object-oriented methodologies to the USA. His detailed account of the object-oriented features and ideas. Readers can be a fast learning information.

Delphi 7 从入门到精通随书源码，写的比较浅显易懂，不过是英文版的，相信对你会有帮助。-Delphi 7 from entry to the source proficient with the book, written in relatively simple words, but is the English version, and I believe that will be helpful to you.

约瑟夫（Joeph）问题的一种描述是：编号为1,2,…,n的n个人按顺时针方向围坐一圈，每人持有一个密码（正整数）。一开始任选一个正整数作为报数上限值m，从第一个人开始按顺时针方向自1开始顺序报数，报到m时停止报数。报m的人出列，将他的密码作为新的m值，从他在顺时针方向上的下一个人开始重新从1报数，如此下去，直至所有人全部出列为止。试设计一个程序求出出列顺序。-Joseph (Joeph) a description of the problem is: numbered 1,2, ..., n, n individuals sitting clockwise circle, each holding a password (positive integer). An optional start a positive integer as the number of reported upper limit of m, from the first person to embark on the clockwise direction starting from a reported sequence number, to report the number of m stop reported. Those who reported m out of the column, his password as the new m value, from his home in a clockwise direction on the next person started to re-reported from a few, and so on, until all of the column until all the up. Try a program designed to find out the column order.

yd601说明文件-yd601 explains the document

一本很好的ASP方面的基础教程-a good basis for the ASP Guide

Java经典试题及答案。里面是一些关于JAVA的资料！-Java classic questions and answers. There is some information on JAVA!