汇编写的俄罗斯方块，在386体系结构下编译运行，蛮好玩的

试下发的上来不，同时，哎哟，搞点资料哦，好难-Examination of the table is not issued at the same time, Oh, come up with something the information Oh,好难

写eeprom的c语言程序，在msp430单片机x1系列上调试通过-EEPROM write the c language program, in the MSP430 family of single-chip debugging through x1

地磅的程序及图纸，-loadometer procedures and drawings,

一个汇编实习作业-a compilation of practical operation

MCD1实战入门篇,点亮单个LED的程序。 该实战的目的作为学习和应用MCD1在线调试工具套件，进行项目的软件和硬件 联合调试的范例程序，也就是当做一个用户程序实例，而演示板暂时充当用户电 路的角色。这样就构成了一个软件、硬件齐全的自制项目模拟环境。 本程序实现的功能是，把端口RC的8条引脚全部设置为输出模式，并让RC0 送出高电平，从而点亮RC0口的一个LED。 该程序可用于PIC16F87X(A)所有系列-Actual entry MCD1 articles, a single LED lit procedures. The real purpose for learning and application debugging MCD1 online suite of tools to carry out the project software and hardware examples of joint commissioning procedures, that is, as a user instance, and the demo board temporarily to serve as the role of the user circuit. This constitutes a software, hardware, a full range of home-made simulation environment projects. Realize the function of this procedure is that the 8-port RC pin all set to output mode, and sent high RC0, so I lit RC0 a LED. The program can be used to PIC16F87X (A) of all series

汇编程序从键盘输入一系列字符,然后按小写字母、数字字符和其他字符分类计数，最-Assembler series of characters from the keyboard and then press the lowercase letters, numbers, characters and other characters were counted, the most

Program in asm for procesador 8086

文本编辑器（A3） 3.3.1设计题目及要求 三， 文本编辑器（10） 要求：（1）编辑文本； （2）保存、打开指定位置的文本文件； （3）具有输入输出界面。-A text editor (A3) 3.3.1 Design and requirements of Title III, a text editor (10) requires: (1) Edit the text (2) to preserve, open the text file specified location (3) with input and output interfaces.

从键盘读入一个四位的十六进制数，CRT显示等值的二进制数. 由于每个十六进制数位对应4个二进制，所以每读入一个十六进制位后，即可将其对应的4个二进制位依次输出。由于数字‘０’~ ‘９’的ASCⅡ码为30H～39H,字母‘a’～‘f’与 ‘A’～‘F’的ASCⅡ码为61H～66H 与41H～46H ，因此，如果输入的字母为数字‘０’～‘９’，则其低４位即为对应的二进制位；如果输入的字符为字母‘ａ’～‘ｆ’或‘Ａ’～‘Ｆ’，则需要减７，然后通过移位将低４位依次输出。 -Reading from the keyboard into a 4 hexadecimal number, CRT display equivalent binary number. Since each hexadecimal number of the corresponding 4-bit binary, so every time into a hexadecimal places, can be its corresponding 4-bit binary sequence output. Due to the number