IEEE754函数源码-Free release of math library, by Sun Microsystems,

Beautiful Architecture -- 英文版 全球19位顶尖架构师智慧结晶 本书围绕5个主题领域来组织本书的内容：概述、企业应用、系统、最终用户应用和编程语言。本书让最优秀的设计师和架构师来描述他们选择的软件架构，剥开架构的各层，展示他们如何让软件做到实现功能、可靠、易用、高效率、可维护、可移植和优雅。-Beautiful Architecture, 1st Edition by Diomidis Spinellis Georgios Gousios ------------------------------------ Publisher: O Reilly Media, Inc. Pub Date: January 29, 2009 -------------------------------------- With this book, you ll discover: How Facebook s architecture is the basis for a data-centric application ecosystem The effect of Xen s well-designed architecture on the way operating systems evolve How community processes within the KDE project help software architectures evolve from rough sketches to beautiful systems How creeping featurism has helped GNU Emacs gain unanticipated functionality The magic behind the Jikes RVM self-optimizable, self-hosting runtime Design choices and building blocks that made Tandem the choice platform in high-availability environments for

在linux上利用ldap和CAS实现单点登陆-In linux using ldap and the CAS to achieve single-point landing

软件测试的入门书籍，非常适合初学者！我看后觉得非常有用-Introduction to software testing books, is very suitable for beginners! I do find it very useful after

信贷资产风险分类计算器适用于农村信用社的贷款五级分类中的!简单实用!-credit risk asset classification calculators apply to loans in rural credit cooperatives in the five classifications. Simple and practical!

ISO/IEC 9899:1990 C编程标准。 1992年的TECHNICAL CORRIGENDUM 1-ISO/IEC 9899:1990 C programming standards. In 1992 the TECHNICAL a correr

徐士良 《Fortran常用算法程序集》(清华大学出版社)的源程序-"Fortran algorithms procedures Set" (Tsinghua University Press), the source

VBAPI函数参考手册 for visual basic。 基本上很全了。-VBAPI function reference manual for visual basic. Basically a very wide.

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected

matlab讲义 多的不说了，开放源代码！就是开放！-matlab handouts do not say more, open source! Is open!

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